java - 读取七个整数值并打印出每个值出现的次数的程序

Question

正如标题所暗示的那样，我正在尝试输入 7 个整数，并能够输出这些整数以及其中有多少重复项的计数。
使用代码:

public static void main(String[] args) {
  Scanner input = new Scanner(System.in);
  int[] userInput = new int[7];
  System.out.print("Enter seven numbers: ");
  for (int i = 0; i < 7; i++) {
    userInput[i] = input.nextInt();
  }
  for (int i = 0; i < 7; i++) {
    int duplicates = 0;
    for (int j = 0; j < 7; j++) {
      if (userInput[i] == userInput[j])
        duplicates++;
    }
    System.out.println("Number " + userInput[i] + " occurs " + duplicates + " times.");
  }
}

输入:12 23 44 22 23 22 55
我的输出中不断出现重复项，如下所示:

Number 12 occurs 1 times.
Number 23 occurs 2 times.
Number 44 occurs 1 times.
Number 22 occurs 2 times.
Number 23 occurs 2 times.
Number 22 occurs 2 times.
Number 55 occurs 1 times.

为了清楚起见，我的目标是:

Number 12 occurs 1 times.
Number 23 occurs 2 times.
Number 44 occurs 1 times.
Number 22 occurs 2 times.
Number 55 occurs 1 times

我感谢任何和所有建议。

Answer 1

您可以使用 vector 来存储每个数字的所有出现次数

public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int[] userInput = new int[7];
System.out.print("Enter seven numbers: ");
for (int i = 0; i < 7; i++) {
  userInput[i] = input.nextInt();
}

int duplicates[] = new int[7];
for(int i = 0; i < 7; i++)
   duplicates[i] = 0;

for (int i = 0; i < 7; i++) {
  for (int j = 0; j < 7; j++) {
    if (userInput[i] == userInput[j])
      duplicates[i]++;
  }
  System.out.println("Number " + userInput[i] + " occurs " + duplicates[i] + " times.");
}
}

输入 12 23 44 22 23 22 55 的输出将会:

Number 23 occurs 2 times.
Number 44 occurs 1 times.
Number 22 occurs 2 times.
Number 23 occurs 2 times.
Number 22 occurs 2 times.
Number 55 occurs 1 times.