CakePHP saveAssociated 不通过模型数据保存 HasMany

Question

我试图让我在 CakePHP 2.3 中的关联模型正确保存，但我遇到了问题。我正在存储帖子，我想知道这些帖子中有哪些链接。对于这些链接中的每一个，如果可用，我想存储 anchor 文本。我的数据库设置如下图所示。

(来源:derekperkins.com)
anchor 模型

class Anchor extends AppModel {

        public $hasMany = array(
            'PostsUrl' => array(
                'className' => 'PostsUrl',
                'foreignKey' => 'anchor_id',
                'dependent' => false
            )
        );

        public function save($data = NULL, $validate = true, $fieldList = array()) {
            $id = Anchor::find('first', array(
                'fields' => array('id'),
                'recursive' => -1,
                'conditions' => array('anchor' => $data['anchor'])
            ));
            if( $id )
                $data['id'] = $id['Anchor']['id'];
            return parent::save($data, $validate, $fieldList);
        }
    }

网址模型

class Url extends AppModel {

    public $hasMany = array(
        'PostsUrl' => array(
            'className' => 'PostsUrl',
            'foreignKey' => 'url_id',
            'dependent' => false
        )
    );

    public function save($data = NULL, $validate = true, $fieldList = array()) {
        $id = Url::find('first', array(
            'fields' => array('id'),
            'recursive' => -1,
            'conditions' => array('url' => $data['url'])
        ));
        if( $id )
            $data['id'] = $id['Url']['id'];
        return parent::save($data, $validate, $fieldList);
    }
}

PostsUrl 模型

class PostsUrl extends AppModel {

    public $belongsTo = array(
        'Post' => array(
            'className' => 'Post',
            'foreignKey' => 'post_id'
        ),
        'Url' => array(
            'className' => 'Url',
            'foreignKey' => 'url_id'
        'Anchor' => array(
            'className' => 'Url',
            'foreignKey' => 'anchor_id'
        )*/
    );
}

岗位模型

class Post extends AppModel {

    public $hasMany = array(
        'PostsUrl' => array(
            'className' => 'PostsUrl',
            'foreignKey' => 'post_id',
            'dependent' => false
        )
    );


    public function save($data = NULL, $validate = true, $fieldList = array()) {
        $id = Post::find('first', array(
            'fields' => array('id'),
            'recursive' => -1,
            'conditions' => array('external_post_id' => $data['external_post_id'])
        ));
        if( $id )
            $data['id'] = $id['Post']['id'];

        return parent::save($data, $validate, $fieldList);
    }
}

提交数据
我创建了一个表单来测试我的模型。这是我用来保存表单创建的数组的代码。我收到一条消息，说内容保存成功，但只有帖子保存。其他三个表中没有输入任何内容。我也在使用 DebugKit 并且没有 SQL 调用引用任何这些数据。

$this->Post->saveAssociated($this->request->data, array('deep' => true))

Array
(
    [Post] => Array
        (
            [external_post_id] => 12345
            [sentiment_score] => 3.3
        )

    [URL] => Array
        (
            [url] => http://test.com
        )

    [Anchor] => Array
        (
            [anchor] => Test Anchor
        )
)

我还尝试将我的数组格式化为将 PostsUrl 下的 URL 和 Anchor 作为子数组，但这也不起作用。
我的 Model::save 函数可以防止我复制数据，并且它们在我过去使用过的其他模型中正常工作(尽管我愿意接受关于更好的方法的建议，因为这使用了数据库调用每张支票)。我也尝试将它们注释掉，它不会影响我的代码。我应该如何构建它以正确保存？

Answer 1

首先是关于你的 Model::save 函数，例如:

public function save($data = NULL, $validate = true, $fieldList = array()) {
    $id = Post::find('first', array(
        'fields' => array('id'),
        'recursive' => -1,
        'conditions' => array('external_post_id' => $data['external_post_id'])
    ));
    if( $id )
        $data['id'] = $id['Post']['id'];

    pr($data);

    return parent::save($data, $validate, $fieldList);
}

它以这种方式打印 $data :

Array
(
    [id] => 3 //for example 3
    [Post] => Array
        (
            [external_post_id] => 12345
            [sentiment_score] => 3.3
        )

    [URL] => Array
        (
            [url] => http://test.com
        )

    [Anchor] => Array
        (
            [anchor] => Test Anchor
        )
)

这个 $data 不正确，正确的数据是:

  Array
    (
        [Post] => Array
            (
                [id] => 3 //for example 3
                [external_post_id] => 12345
                [sentiment_score] => 3.3
            )

        [URL] => Array
            (
                [url] => http://test.com
            )

        [Anchor] => Array
            (
                [anchor] => Test Anchor
            )
    )

您必须以这种方式更改 Model::save 函数:

public function save($data = NULL, $validate = true, $fieldList = array()) {
    $id = Post::find('first', array(
        'fields' => array('id'),
        'recursive' => -1,
        'conditions' => array('external_post_id' => $data['external_post_id'])
    ));
    if( $id )
        $data[$this->name]['id'] = $id['Post']['id'];

    return parent::save($data, $validate, $fieldList);
}

其次，你不能用单次保存来保存这些数据，你应该这样保存你的数据:

$postData = array
(
    'Post' => array
        (
            'external_post_id' => 12345
            'sentiment_score' => 3.3
        )
);

$this->Post->save($data);

$postUrlId = $this->PostsUrl->find('first', array(
'conditions' => array(
                   'post_id' => $this->Post->id
                     ),
'fields' => array('id')
));

$urlAnchorData = array(
    'URL' => array
        (
            'url' => 'http://test.com'
        ),
    'Anchor' => array
        (
            'anchor' => 'Test Anchor'
        ),
    'PostsUrl' => array(
            'id' => $postUrlId['PostsUrl']['id']
     )
);

$this->PostsUrl->saveAll('$urlAnchorData');