python - 如何在函数循环之外定义参数？

Question

我正在尝试执行一个函数，如果在我的 while 语句中看到正确的输入，该函数将重复。但是我的程序在附加循环中返回相同的值而没有选择使用新的 hrs和 rate如果我的输入语句高于我的函数，则输入。如果它们在当前呈现的函数内，它会说明我的 (hrs,rate)没有定义。 我将如何定义 hrs和 rate参数同时保持我的输入在函数内？

def CalPay(hrs,rate):
    hrs = input('Please enter number of hours worked for this week:')
    rate = input('What is hourly rate:')
    try:
        hrs = float(hrs)
    except:
        hrs = -1
    try:
        rate = float(rate)
    except:
        rate = -1
    if hrs <= 0 :
        print('You have entered wrong information for hours.')
    elif rate <= 0 :
        print('You have entered wrong rate information.')
    elif hrs <=  40 :
        pay = hrs * rate
        print ('Your pay for this week is:', pay)
    elif hrs > 40 and hrs < 60 :
        pay = ((hrs - 40) * (rate * 1.5)) + (40 * rate)
        print ('Your pay for this week is:', pay)
    elif hrs >= 60 :
        pay = ((hrs - 60) * (rate * 2.0)) + (20 * (rate * 1.5)) + (40 * rate)
        print ('Your pay for this week is:', pay)

while True:
    CalPay(hrs,rate)
    yn = input('Do you wish to repeat this program? (y/n)').lower()
    if yn == 'y' :
        continue 
    if yn == 'n' :
        break
print ('Done!')

Answer 1

首先，您需要在函数之后初始化两个变量，因此每当您输入变量的值时，它们都必须被定义。
类似的东西 :

# those two lines will be after the function
hrs = 0   
rate = 0

完整的程序会这样 :-

def CalPay(hrs,rate):
    hrs = input('Please enter number of hours worked for this week:')
    rate = input('What is hourly rate:')
    try:
        hrs = float(hrs)
    except:
        hrs = -1
    try:
        rate = float(rate)
    except:
        rate = -1
    if hrs <= 0 :
        print('You have entered wrong information for hours.')
    elif rate <= 0 :
        print('You have entered wrong rate information.')
    elif hrs <=  40 :
        pay = hrs * rate
        print ('Your pay for this week is:', pay)
    elif hrs > 40 and hrs < 60 :
        pay = ((hrs - 40) * (rate * 1.5)) + (40 * rate)
        print ('Your pay for this week is:', pay)
    elif hrs >= 60 :
        pay = ((hrs - 60) * (rate * 2.0)) + (20 * (rate * 1.5)) + (40 * rate)
        print ('Your pay for this week is:', pay)


hrs = 0
rate = 0

while True:
    CalPay(hrs,rate)
    yn = input('Do you wish to repeat this program? (y/n)').lower()
    if yn == 'y' :
        continue 
    if yn == 'n' :
        break
print ('Done!')

输出

Please enter number of hours worked for this week: 36
What is hourly rate: 6
Your pay for this week is: 216.0
Do you wish to repeat this program? (y/n)Y

Please enter number of hours worked for this week: 12
What is hourly rate: 5
Your pay for this week is: 60.0
Do you wish to repeat this program? (y/n)