node.js - 退出 Array.map() 循环

Question

我有以下代码

const getCompanies = async (searchURL) => {
    const html = await rp(baseURL + searchURL);
    const businessMap = cheerio('a.business-name', html).map(async (i, e) => {
        const phone = cheerio('p.phone', innerHtml).text();
        if (phone == 123) {
            exit;
        }
        return {
            phone,
        }
    }).get();
    return Promise.all(businessMap);
};

如果我的条件匹配，我想退出循环。有什么办法，如果条件匹配，则立即返回数据。并停止执行循环

Answer 1

您的用例将更适合 Array.some而不是 Array.map

The some() method tests whether at least one element in the array passes the test implemented by the provided function. It returns a Boolean value.

因此，只要数组中的任何项目与条件匹配，它就会停止执行。
您可以在旁边使用外部变量来捕获匹配的值，例如:

const getCompanies = async (searchURL) => {
    const html = await rp(baseURL + searchURL);
    let businessMap;
    cheerio('a.business-name', html).some(async (i, e) => {
            const phone = cheerio('p.phone', innerHtml).text();

            if(phone == 123) {
               // condition matched so assign data to businessMap here
               // and return true so that execution stops
              return true;
            }       
       });
    return Promise.all(businessMap);
    };