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python - 如何将飞扬的小鸟游戏的分数存储到 sql 数据库中

转载 作者:行者123 更新时间:2023-12-04 08:27:33 25 4
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我是pygame的初学者(使用python idle),做了一个简单的游戏Flappy Bird作为我的学校项目。它需要以某种方式与 SQL 数据库连接,我将分数与玩家姓名一起存储在其中。但是在完成一轮游戏并输入上述信息后,它在调用所需功能后并没有重新启动(GUI挂起)并不断要求输入玩家姓名(空闲)。此外,信息不会存储在 SQL 数据库中。我尝试将分数保存在文本文件中并打印输出,但也在那里发生了同样的问题。这是代码:

import pygame
import random
import mysql.connector as c

# Initialising the modules in pygame
pygame.init()

SCREEN = pygame.display.set_mode((500, 750)) # Setting the display

# background
BACKGROUND_IMAGE = pygame.image.load('background.jpg')

# BIRD
BIRD_IMAGE = pygame.image.load('bird1.png')
bird_x = 50
bird_y = 300
bird_y_change = 0

def display_bird(x, y):
SCREEN.blit(BIRD_IMAGE, (x, y))

# OBSTACLES
OBSTACLE_WIDTH = 70
OBSTACLE_HEIGHT = random.randint(150,450)
OBSTACLE_COLOR = (211, 253, 117)
OBSTACE_X_CHANGE = -4
obstacle_x = 500

def display_obstacle(height):
pygame.draw.rect(SCREEN, OBSTACLE_COLOR, (obstacle_x, 0, OBSTACLE_WIDTH, height))
bottom_obstacle_height = 635 - height - 150
pygame.draw.rect(SCREEN, OBSTACLE_COLOR, (obstacle_x, 635, OBSTACLE_WIDTH, -bottom_obstacle_height))

# COLLISION DETECTION
def collision_detection (obstacle_x, obstacle_height, bird_y, bottom_obstacle_height):
if obstacle_x >= 50 and obstacle_x <= (50 + 64):
if bird_y <= obstacle_height or bird_y >= (bottom_obstacle_height - 64):
return True
return False

# SCORE
score = 0
SCORE_FONT = pygame.font.Font('freesansbold.ttf', 32)


def sql():
m=c.connect(host="localhost",user="root",password= "password",database="flappy
bird")
my=m.cursor()
n=input('enter your name')
r = maximum
my.execute("insert into table(name, score) values({},'{}')".format(n,r))
m.commit()
my.execute("select * from table")
for i in my:
print(i)

def score_display(score):
display = SCORE_FONT.render(f"Score: {score}", True, (255,255,255))
SCREEN.blit(display, (10, 10))

# START SCREEN
startFont = pygame.font.Font('freesansbold.ttf', 32)
def start():
# displays: "press space bar to start)
display = startFont.render(f"PRESS SPACE BAR TO START", True, (255, 255, 255))
SCREEN.blit(display, (20, 200))
pygame.display.update()

# GAME OVER SCREEN
# This list will hold all of the scores
score_list = [0]

game_over_font1 = pygame.font.Font('freesansbold.ttf', 64)
game_over_font2 = pygame.font.Font('freesansbold.ttf', 32)

def game_over():
# check for the maximum score
global maximum
maximum = max(score_list)
# "game over"
display1 = game_over_font1.render(f"GAME OVER", True, (200,35,35))
SCREEN.blit(display1, (50, 300))
# shows your current score and your max score
display2 = game_over_font2.render(f"SCORE: {score} MAX SCORE: {maximum}", True,
(255, 255, 255))
SCREEN.blit(display2, (50, 400))
# If your new score is the same as the maximum then u reached a new high score
if score == maximum:
display3 = game_over_font2.render(f"NEW HIGH SCORE!!", True, (200,35,35))
SCREEN.blit(display3, (80, 100))

running = True
# waiting is going to refer to our end or start screen
waiting = True
# set collision to false in the beginning so that we only see the start screen in
the beginning
collision = False

while running:

SCREEN.fill((0, 0, 0))

# display the background image
SCREEN.blit(BACKGROUND_IMAGE, (0, 0))

# we will be sent into this while loop at the beginning and ending of each game
while waiting:
if collision:
# If collision is True (from the second time onwards) we will see both the end screen and the start screen
game_over()
sql()
start()



else:
# This refers to the first time the player is starting the game
start()

for event in pygame.event.get():
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_SPACE:
# If we press the space bar we will exit out of the waiting while loop and start to play the game
# we will also reset some of the variables such as the score and the bird's Y position and the obstacle's starting position
score = 0
bird_y = 300
obstacle_x = 500
# to exit out of the while loop
waiting = False

if event.type == pygame.QUIT:
# in case we exit out make both running and waiting false
waiting = False
running = False

for event in pygame.event.get():
if event.type == pygame.QUIT:
# If you press exit you exit out of the while loop and pygame quits
running = False

if event.type == pygame.KEYDOWN:
if event.key == pygame.K_SPACE:
# if you press spacebar you will move up
bird_y_change = -6

if event.type == pygame.KEYUP:
if event.key == pygame.K_SPACE:
# when u release space bar you will move down automatically
bird_y_change = 3

# moving the bird vertically
bird_y += bird_y_change
# setting boundaries for the birds movement
if bird_y <= 0:
bird_y = 0
if bird_y >= 571:
bird_y = 571

# Moving the obstacle
obstacle_x += OBSTACE_X_CHANGE

# COLLISION
collision = collision_detection(obstacle_x, OBSTACLE_HEIGHT, bird_y, OBSTACLE_HEIGHT
+ 150)

if collision:
# if a collision does occur we are gonna add that score to our list of scores and make waiting True
score_list.append(score)
waiting = True

# generating new obstacles
if obstacle_x <= -10:
obstacle_x = 500
OBSTACLE_HEIGHT = random.randint(200, 400)
score += 1
# displaying the obstacle
display_obstacle(OBSTACLE_HEIGHT)

# displaying the bird
display_bird(bird_x, bird_y)

# display the score
score_display(score)


# Update the display after each iteration of the while loop
pygame.display.update()

# Quit the program

pygame.quit()
请告诉我问题以及如何解决。谢谢!

最佳答案

问题是您没有完全重置游戏状态。因此,当新游戏开始时,玩家下方立即仍然存在障碍。
也许让你的 start()函数也重置所有这些字段:

def start():
# displays: "press space bar to start)
display = startFont.render(f"PRESS SPACE BAR TO START", True, (255, 255, 255))
SCREEN.blit(display, (20, 200))
pygame.display.update()

# reset for new game
score = 0
bird_x = 50
bird_y = 300
bird_y_change = 0
OBSTACLE_WIDTH = 70
OBSTACLE_HEIGHT = random.randint(150,450)
OBSTACLE_COLOR = (211, 253, 117)
OBSTACE_X_CHANGE = -4
obstacle_x = 500

关于python - 如何将飞扬的小鸟游戏的分数存储到 sql 数据库中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/65191608/

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