C语言，改变char变量

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int main()            
{  
      charactername="tom";        
      characterage=78;       
      printf("his name is %s\n", charactername);        
      printf("his age is %d\n", characterage);         

      characterage=78;
      charactername="John";
      printf("his name changed to %s\n", charactername);
      printf("his age changed to %d\n", characterage);
 
      return 0;
}
    

当我在代码之间更改字符名称时，代码不会运行，而如果我只更改年龄代码运行完美，为什么我不能更改字符变量但我可以更改字符年龄？？(在 c 语言中)

Answer 1

两件事情:

您必须定义变量的类型。

无法分配数组。

在您的代码中，您需要进行一些更改(在下面的注释中标记)

#include <stdio.h>
#include <string.h>
                                                 // header files are needed
#define ARRSIZ 64                               // choose any size you like 
int main(void)                                  // proper signature
{  
      char charactername[ARRSIZ]="tom";        //define a char array and initialize it.
      int characterage=78;                     // type is a must
      printf("his name is %s\n", charactername);        
      printf("his age is %d\n", characterage);         

      characterage=78;                           // this is fine, only assignment
      strcpy(charactername,"John");              // use strcpy to copy to an array
      printf("his name changed to %s\n", charactername);
      printf("his age changed to %d\n", characterage);
 
      return 0;
}