javascript - 在 PHP 中作为单独页面导航

Question

我正在使用我的 导航作为一个单独的页面是 Navigation.php我正在通过 <?php include 'header.php'; ?> 添加此页面在每一页。
但是当我去一个页面时，例如:去关于 页，那个关于 导航栏中的按钮有一个类 class='active'和那个类通过 javascript 添加。
当我进入二级页面时，问题就来了，例如:Portfolio > Portfolio Item该脚本没有在 Portfolio 上添加类按钮。
Navigation.php页面:

<ul class="nav nav-pills" id="mainNav">
    <li <?php echo (basename($_SERVER['PHP_SELF']) == 'index.php') ? 'class="active"' : ''; ?>>
        <a class="nav-item nav" href="/home">
            Home
        </a>
    </li>
    <li <?php echo (basename($_SERVER['PHP_SELF']) == 'about.php') ? 'class="active"' : ''; ?>>
        <a class="nav-item"  href="/about">
            About
        </a>
    </li>
    <li <?php echo (basename($_SERVER['PHP_SELF']) == 'services.php') ? 'class="active"' : ''; ?>>
        <a class="nav-item"  href="/services">
            Services
        </a>
    </li>
    <li <?php if ((basename($_SERVER['SCRIPT_FILENAME'], '.php')) == 'portfolio' or 'portfolioItem') echo "class='active'";?>>
        <a class="nav-item"  href="/portfolio">
            Portfolio
        </a>
    </li>
    <li <?php echo (basename($_SERVER['PHP_SELF']) == 'showcase.php') ? 'class="active"' : ''; ?>>
        <a class="nav-item"  href="/showcase">
            Showcase
        </a>
    </li>
    <li <?php echo (basename($_SERVER['PHP_SELF']) == 'blog.php') ? 'class="active"' : ''; ?>>
        <a class="nav-item"  href="/blog">
            Blog
        </a>
    </li>
    <li <?php echo (basename($_SERVER['PHP_SELF']) == 'contact.php') ? 'class="active"' : ''; ?>>
        <a class="nav-item"  href="/contact">
            Contact
        </a>
    </li>
</ul>

Javascript我正在使用:

<script>
  $(function () {
      var pgurl = window.location.href.substr(window.location.href.lastIndexOf("/") + 1);
      $("nav-pills ul li").each(function () {
          if ($(this).attr("href") == pgurl) {
              $(this).parent().addClass('active');
          }
          if ((($(this).attr("href") == 'index.php')||($(this).attr("href") == '')) && (pgurl == '')) {
              $(this).parent().addClass("active");
          }
      })
  });
</script>

Answer 1

请尝试更改

<?php if ((basename($_SERVER['SCRIPT_FILENAME'], '.php')) == 'portfolio' or 'portfolioItem') echo "class='active'";?>>

到

<?php if ( (basename($_SERVER['SCRIPT_FILENAME'], '.php')) == 'portfolio.php' || (basename($_SERVER['SCRIPT_FILENAME'], '.php')) == 'portfolioItem.php'  ) { echo "class='active'"; }  ?>>