c++ - 我想打印单词的缩写，但不知道我做错了什么

Question

我想打印单词的缩写
编写一个 C 程序，该程序应将用户的组织名称作为字符串。您必须在该字符串上实现以下函数:
例如:
字 = 巴基斯坦国家石油
缩写:PSO
仅来自单词的大写字母
它仅打印 1 个字。
代码 :

#include <iostream>
using namespace std;

void printAbbrevation(char Word[], char WordAbb[]);
int findLength(char Word[])
{
    int length = 0;

    for (int i = 0; Word[i] != '\0'; i++)
    {
        length++;
    }
    return length;
}

void findAbbrevation(char Word[])
{
    int WordLength = findLength(Word);
    char WordAbb[] = {0};
    
    for (int i = 0; i < WordLength; i++)
    {
        if (Word[i] >= 'A' && Word[i] <= 'Z')
        {
            WordAbb[i] = Word[i];
        }
    }
    printAbbrevation(Word, WordAbb);
}

void printAbbrevation(char Word[], char WordAbb[])
{
    int abbword = findLength(WordAbb);
    cout << "Abbrevation of " << Word << " is = ";

    for (int i = 0; i < abbword; i++)
    {
        cout << WordAbb[i];
    }
    
}

int main()
{
    char Word[100] = {0};
    cout << "Enter the Word = ";
    cin.getline(Word,100);
    cout << "Length of Word is = ";
    cout << findLength(Word);
    cout << endl;
    findAbbrevation(Word);
    return 0;
}

我得到的输出:

Answer 1

您需要更改您的 findAbbrevation()像这样的功能:

void findAbbrevation(char Word[])
{
    int WordLength = findLength(Word);
    char WordAbb[25] = {0};
    int j = 0;
    
    int flag = 0;
    for (int i = 0; i < WordLength; i++)
    {
        // To continue untill we get a space
        // this marks the start of the new word
        if(flag)
        {
            if(Word[i] == ' ')
            {
                flag = 0;
            }
            continue;
        }
        else
        {
            if (Word[i] >= 'A' && Word[i] <= 'Z')
            {
                WordAbb[j++] = Word[i];
                flag = 1;
            }
        }
    }
    printAbbrevation(Word, WordAbb);
}

我所做的更改是:

找到新单词时保留一个标志，这是通过检查字符串中的空格来完成的。

对于找到的每个新单词，将它的第一个字符添加到缩写字符串中。

为缩写字符串保留一个单独的计数器。