javascript - 我将如何在对象数组中连接和分组相似的值

Question

我有一个对象数组

const array = [
   {keyA: "HG 386893", count: 1, type: "dha"},
   {keyA: "AL 386893", count: 1, type: "gop"},
   {keyA: "HG 386893", count: 2, type: "ind"},
   {keyA: "NC 386893", count: 1, type: "dha"},
   {keyA: "HG 386893", count: 1, type: "gop"},
   {keyA: "RO 386893", count: 1, type: "ind"}
];

我想合并基于类似的 key keyA属性(property)和连接 type并添加 count .所以最终结果将是:

const result = [
   {keyA: "HG 386893", count: 4, type: "dha,ind,gop"},
   {keyA: "AL 386893", count: 1, type: "gop"},
   {keyA: "NC 386893", count: 1, type: "dha"},
   {keyA: "RO 386893", count: 1, type: "ind"}
];

我实现的方式是:

对数组进行排序 keyA

循环遍历已排序的数组 & 如果前一个值 = 当前值，则添加 count并连接 type

我知道这不是最佳解决方案，所以我需要一些帮助以更好的方式优化它。谢谢!

Answer 1

您可以使用 .reduce :

const array = [
  { keyA: "HG 386893", count: 1, type: "dha" },
  { keyA: "AL 386893", count: 1, type: "gop" },
  { keyA: "HG 386893", count: 2, type: "ind" },
  { keyA: "NC 386893", count: 1, type: "dha" },
  { keyA: "HG 386893", count: 1, type: "gop" },
  { keyA: "RO 386893", count: 1, type: "ind" }
];

const grouped = Object.values(array.reduce((acc,item) => {
  const { keyA, count, type } = item;
  const prev = acc[keyA];
  acc[keyA] = prev 
    ? { ...item, count: prev.count+count, type: `${prev.type},${type}` } 
    : item;
  return acc;
}, {}));

console.log(grouped);