python - 从python到PHP的for循环转换问题

Question

我尝试转换以下 Python 函数:

def Sous(dist,d):

    l = len(dist)
    L = [[]]
    for i in range(l):
        K = []
        s = sum(dist[i+1:])
        for p in L:
            q = sum(p)
            m = max(d - q - s, 0)
            M = min(dist[i], d - q)
            for j in range(m, M+1):
                K.append(p + [j])
        L = K
    return L

进入一个 PHP 函数:

function sous($dist, $d){
    $l = count($dist);
    $L = [[]];
    foreach(range(0,$l) as $i){
        $K = [];
        $s = array_sum(array_slice($dist, $i+1));
        foreach($L as $p){
            $q = array_sum($p);
            $m = max($d-$q-$s, 0);
            $M = min($dist[$i], $d-$q);
            foreach(range($m, $M+1) as $j){
                $K[] = $p+$j;
            }
        }
        $L = $K;
    }
    return $L;
}

当我测试它时:

var_dump(sous([3,2,2,1,1,0], 2));

我收到错误:

Uncaught Error: Unsupported operand types

对于线

$K[] = $p+$j;

我不知道如何解决它，你有什么想法吗？

Answer 1

Python的range(n)从 0 返回一个数组至 n-1而 PHP 的 range($n, $m)从 $n 返回一个数组至 $m ，所以你必须使用 range(0, $l -1)那里。
还有 K.append(p+[j])应转换为 $K[] = $p+[$j];自 $j不是数组。
以下功能应该工作:

function sous($dist, $d){
    $l = count($dist);
    $L = [[]];
    foreach(range(0,$l - 1) as $i){
        $K = [];
        $s = array_sum(array_slice($dist, $i+1));
        foreach($L as $p){
            $q = array_sum($p);
            $m = max($d-$q-$s, 0);
            $M = min($dist[$i], $d-$q);
            foreach(range($m, $M+1) as $j){
                $K[] = $p+[$j];
            }
        }
        $L = $K;
    }
    return $L;
}