sql - 获得一个不同的行及其值

Question

所以我想得到预期的结果，同时使用子查询但我的答案不会计划，下面是我的代码和结果与我的预期结果

SELECT "Invoice"."BillingCountry", "Genre"."Name", COUNT("Track"."TrackId") FROM "Track"
INNER JOIN "Genre"
ON "Track"."GenreId" = "Genre"."GenreId"
INNER JOIN "InvoiceLine" 
ON "Track"."TrackId" = "InvoiceLine"."TrackId"
INNER JOIN "Invoice"
ON "InvoiceLine"."InvoiceId" = "Invoice"."InvoiceId"
WHERE "Invoice"."BillingCountry" in  ('USA', 'Canada', 'Brazil', 'france', 'Germany')
GROUP BY "Genre"."GenreId", "Invoice"."BillingCountry"
ORDER BY COUNT("Track"."TrackId") DESC 
LIMIT 10


billingcountry | name |  count
       usa       bat      50
       canada    bat      43
       usa       car      40
       usa       toy      39
       germany   bat      36
       france    bat      34
       canada    bike     20
       usa       fing     15
       brazil    bat      14
       france    shoe     10

预期结果

country    | item |  count
   usa       bat      50
   canada    bat      43
   germany   bat      36
   france    bat      34
   brazil    bat      14
   

我知道这里有类似的解决方案，但我不能让它们工作，如果有人可以提供帮助，我将不胜感激

Answer 1

您似乎想要每个国家/地区最受欢迎的类型。如果是这样，请使用 DISTINCT ON :

SELECT DISTINCT ON (i."BillingCountry") i."BillingCountry", g."Name", COUNT(*)
FROM "Track" t JOIN
     "Genre" g
     ON t."GenreId" = g."GenreId" JOIN
     "InvoiceLine" il
     ON t."TrackId" = il."TrackId" JOIN
     "Invoice" i
     ON il."InvoiceId" = i."InvoiceId"
WHERE i."BillingCountry" in  ('USA', 'Canada', 'Brazil', 'France', 'Germany')
GROUP BY g."GenreId", i."BillingCountry"
ORDER BY i."BillingCountry", COUNT(*) DESC ;

请注意表别名如何使查询更易于编写和阅读。我还会修复表定义，这样您就不必转义表名和列名——不得不转义它们是一种非常非常糟糕的做法。