c - 用C编写一个程序，使用函数显示偶数和奇数自然数的n项及其总和

Question

#include <stdio.h>

int sum_even(int n);
int sum_odd(int m);

int main() {
    int n;
    scanf("%d", &n);

    int m;
    scanf("%d", &m);

    int evensum;
    evensum = sum_even(int n);

    int oddsum;
    oddsum = sum_odd(int m);

    printf("the sum of even numbers is %d", evensum);
    printf("the sum of odd numbers is %d", oddsum);

    return 0;
}

int sum_even(int n) {
    int sum = 0, i;
    for (i = 2; i <= n; i += 2) {
        sum += i;
    }
    return sum;
}

int sum_odd(int m) {
    int SUM = 0, j;
    for (j = 1; j <= m; j = j + 2) {
        SUM = SUM + j;
    }
    return SUM;
}

请告诉我什么是错我的代码，我是新来的编码，我是能够解决的问题，而无需使用功能，但我很困惑，当我不得不使用功能

Answer 1

在调用函数时，您只需传递参数而不指定其数据类型。
即你会这样写:-

evensum = sum_even(n);
oddsum = sum_odd(m);

调用返回值的函数的一般语法是:-

return-value = function-name(arg-list);