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Java 正则表达式组

转载 作者:行者123 更新时间:2023-12-04 07:56:54 26 4
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import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class hw2 {

static char[] evaluate(String input) throws IllegalArgumentException
{
input = input.replaceAll("\\p{Z}", "");

String result_num1 = null;
String result_op = null;
String result_num2 = null;

Pattern pattern_num = Pattern.compile("([+-][0-9]*)([+-/*])([+-]\\d*)");
Matcher matcher_num = pattern_num.matcher(input);

while(matcher_num.find()) {
result_num1 = matcher_num.group(1);
result_op = matcher_num.group(2);
result_num2 = matcher_num.group(3);
}

System.out.println(result_num1);
System.out.println(result_op);
System.out.println(result_num2);

return element_2;
}

public static void main(String[] args) throws Exception{

InputStreamReader isr = new InputStreamReader(System.in);
BufferedReader reader = new BufferedReader(isr);
String input = reader.readLine();

char[] result = evaluate(input);
System.out.println(result);

}
}

任何人都可以请指导这一点。
输入:300 + 25
预期输出:
300
+
25
+
输出:
空值
空值
空值

最佳答案

根据您显示的样本,您能否尝试以下操作。

([+-]?\\d+)([-+/*])([+-]?\\d+)
说明:为上述添加详细说明。
([+-]?\\d+)  ##Creating first group which checks if there is either +/- present(as optional) following with 1 or more occurrences.
([-+/*]) ##Creating 2nd group and checking if +/- or / is present
([+-]?\\d+) ##Creating 3rd group which checks if there is either +/- present(as optional) following with 1 or more occurrences.

关于Java 正则表达式组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/66657372/

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