selenium-webdriver - 如何在Selenium WebDriver中单击网页中的所有链接

Question

我有10个不同的页面包含不同的链接。如何点击所有链接？

条件是:
我)我不知道有多少个链接
ii)我要计算并单击每个链接

请给我建议Selenium WebDriver脚本。

Answer 1

捕获并浏览网页上的所有链接

迭代器和高级for循环可以完成类似的工作；但是，可以使用数组概念解决循环内页面导航上的不一致。

private static String[] links = null;
private static int linksCount = 0;

driver.get("www.xyz.com");
List<WebElement> linksize = driver.findElements(By.tagName("a")); 
linksCount = linksize.size();
System.out.println("Total no of links Available: "+linksCount);
links= new String[linksCount];
System.out.println("List of links Available: ");  
// print all the links from webpage 
for(int i=0;i<linksCount;i++)
{
links[i] = linksize.get(i).getAttribute("href");
System.out.println(all_links_webpage.get(i).getAttribute("href"));
} 
// navigate to each Link on the webpage
for(int i=0;i<linksCount;i++)
{
driver.navigate().to(links[i]);
Thread.sleep(3000);
}

1 |捕获特定frame | class | id下的所有链接并逐一导航

driver.get("www.xyz.com");  
WebElement element = driver.findElement(By.id(Value));
List<WebElement> elements = element.findElements(By.tagName("a"));
int sizeOfAllLinks = elements.size();
System.out.println(sizeOfAllLinks);
for(int i=0; i<sizeOfAllLinks ;i++)
{
System.out.println(elements.get(i).getAttribute("href"));
}   
for (int index=0; index<sizeOfAllLinks; index++ ) {
getElementWithIndex(By.tagName("a"), index).click();
driver.navigate().back();
}

public WebElement getElementWithIndex(By by, int index) {
WebElement element = driver.findElement(By.id(Value));
List<WebElement> elements = element.findElements(By.tagName("a")); 
return elements.get(index);
}

2 |捕获所有链接[替代方法]

java

driver.get(baseUrl + "https://www.google.co.in");
List<WebElement> all_links_webpage = driver.findElements(By.tagName("a")); 
System.out.println("Total no of links Available: " + all_links_webpage.size());
int k = all_links_webpage.size();
System.out.println("List of links Available: ");
for(int i=0;i<k;i++)
{
if(all_links_webpage.get(i).getAttribute("href").contains("google"))
{
String link = all_links_webpage.get(i).getAttribute("href");
System.out.println(link);
}   
}

Python

from selenium import webdriver

driver = webdriver.Firefox()
driver.get("https://www.google.co.in/")
list_links = driver.find_elements_by_tag_name('a')

for i in list_links:
        print i.get_attribute('href')

driver.quit()