json - jq - 根据其中一个值查找 JSON 对象并从中获取另一个值

Question

我最近才开始使用 jq，我想知道这样的事情是否可能。

例子:

{
  "name": "device",
  "version": "1.0.0",
  "address": [
    {
      "address": "10.1.2.3",
      "interface": "wlan1_wifi"
    },
    {
      "address": "10.1.2.5",
      "interface": "wlan2_link"
    },
    {
      "address": "10.1.2.4",
      "interface": "ether1"
    }
  ],
  "wireless": [
    {
      "name": "wlan1_wifi",
      "type": "5Ghz",
      "ssid": "wifi"
    },
    {
      "name": "wlan2_link",
      "type": "2Ghz",
      "ssid": "link"
    }
  ]
}

首先让我们将示例转换为这个 json 对象:

cat json | jq '. | {"name": ."name", "version": ."version", "wireless": [."wireless"[] | {"name": ."name", "type": ."type", "ssid": ."ssid"}]}'
{
  "name": "device",
  "version": "1.0.0",
  "wireless": [
    {
      "name": "wlan1_wifi",
      "type": "5Ghz",
      "ssid": "wifi"
    },
    {
      "name": "wlan2_link",
      "type": "2Ghz",
      "ssid": "link"
    }
  ]
}

现在有一个问题。我需要为 "wireless" 分配一个地址大批。地址存储在 "address"大批。

所以问题是:有没有办法在 "address" 中找到正确的 json 对象？基于 "name" (在无线阵列中)和“interface"(在地址阵列中)用于 "wireless" 阵列中的每个 json 对象，然后将 "address" 分配给它？

最终结果应如下所示:

{
  "name": "device",
  "version": "1.0.0",
  "wireless": [
    {
      "name": "wlan1_wifi",
      "type": "5Ghz",
      "ssid": "wifi",
      "address": "10.1.2.3"
    },
    {
      "name": "wlan2_link",
      "type": "2Ghz",
      "ssid": "link",
      "address": "10.1.2.5"
    }
  ]
}

答案:
这是我基于 answer 的回答来自@peak。而不是复制 .wireless 的内容然后使用 map ，我正在挑选我只想包含的键。这也让我可以随意定位“地址”。

(INDEX(.address[]; .interface)) as $dict 
| {name: .name, version: .version, 
wireless: [.wireless[] | {name, address: ($dict[.name]|.address), type, ssid}]}

Answer 1

以下生成最初要求的输出:

(.wireless[].name) as $name
| .address[]
| select(.interface == $name)
| { wireless: {name: $name, address}}

但是，上述过滤器可能会产生多个结果，因此您可能需要进行相应的修改。

订正订正要求

如果你的 jq 有 INDEX/2 (仅在 jq 1.5 发布后才可用)，您可以简单地使用它来创建查找表:

(INDEX(.address[]; .interface)) as $dict
| {name,
   version,
   wireless: (.wireless
              | map(. + {address: ($dict[.name]|.address) }) ) }

或者(可能取决于确切的要求):

(INDEX(.address[]; .interface)) as $dict
| del(.address)
| .wireless |= map(. + {address: ($dict[.name]|.address) })

如果您的 jq 没有 INDEX/2 ，那么您可以轻松地调整上述内容(使用 reduce )，或者更轻松地获取 INDEX/2 的定义来自 https://github.com/stedolan/jq/blob/master/src/builtin.jq