python - 写入 Pickle 文件时出现 FileNotFoundError

Question

我在 list 中获取某个目录中的所有文件名，并想将此列表写入 pickle文件。这是我正在使用的代码:

import _pickle as pickle
with open(filepath+'filenames.pkl', 'wb') as f:
    pickle.dump(filenames, f)

这给了我以下错误:

---------------------------------------------------------------------------
FileNotFoundError                         Traceback (most recent call last)
<ipython-input-32-c59e6889d2fe> in <module>()
      1 import _pickle as pickle
----> 2 with open(dpath+'filenames.pkl', 'wb') as f:
      3     pickle.dump(filenames, f)

FileNotFoundError: [Errno 2] No such file or directory: '/data/train/filenames.pkl'

我应该创建这个文件。为什么这个文件是预期的？
(我使用的是 Python 3.6。)

Answer 1

在你的情况下很可能 /data/train/目录不存在

我试过这段代码并得到同样的错误:

import pickle as pickle
filenames='sadasdas'
with open('/tmp/not_exist/filenames.pkl', 'wb') as f:
    pickle.dump(filenames, f)

输出:

---------------------------------------------------------------------------
FileNotFoundError                         Traceback (most recent call last)
<ipython-input-7-6a22c2148796> in <module>()
      1 import pickle as pickle
      2 filenames='sadasdas'
----> 3 with open('/tmp/not_exist/filenames.pkl', 'wb') as f:
      4     pickle.dump(filenames, f)

FileNotFoundError: [Errno 2] No such file or directory: '/tmp/not_exist/filenames.pkl'

您可以通过在写入文件之前确保目录存在来处理此问题:执行相同操作的编程方法是这样的

import os
filename = "/tmp/not_exist/filenames.pkl"
os.makedirs(os.path.dirname(filename), exist_ok=True)
data = 'sadasdas'
with open('/tmp/not_exist/filenames.pkl', 'wb') as f:
    pickle.dump(data, f)

引用: https://stackoverflow.com/a/12517490/3027854