python - 实现一种让我的 tron 角色无法通过自己的方法

Question

我正在努力做到这一点，所以如果你在我的 tron 游戏中进入自己，你会死，就像在经典的街机游戏中一样。我已经实现了它，所以如果你触摸其他玩家你会死，但我似乎无法弄清楚如何做到这一点，所以如果你要击中自己，你也会输。我将如何实现此功能以使游戏更像经典 tron？

import pygame
import sys
pygame.init()

black = 0,0,0 #Create black for background
blue = 0,0,225 #Create blue for player 1
red = 255,0,0 #Create red for player 2

class Player:
    def __init__(self, screen, x, y, w, h, dx, dy, color, tron_path):
        self.x = x #X coord
        self.y = y #Y coord
        self.w = w
        self.h = h
        self.dx = dx
        self.dy = dy
        self.color = color #color
        self.screen = screen
        self.tron_path = tron_path
        self.player_rect = pygame.Rect(self.x, self.y, self.w, self.h)
    
    def move(self):
        self.player_rect[0] += self.dx #changes rect's x-coordinate 
        self.player_rect[1] += self.dy #changes rect's y-coordinate

        #self.tron_path.append(self.player_rect) 
        self.tron_path.append(self.player_rect.copy())
    
    def draw(self):
        pygame.draw.rect(self.screen, self.color, self.player_rect)
    

screen = pygame.display.set_mode((1000, 750))  # creates window
pygame.display.set_caption("Tron")  # sets window title
clock = pygame.time.Clock()

players = []
tron_path_1 = []
tron_path_2 = []
p1 = Player(screen, 100, 100, 5, 5, 1, 0, blue, tron_path_1)  # creates p1
p2 = Player(screen, 500, 500, 5, 5, 1, 0, red, tron_path_2) #create p2
screen.fill(black)
players.append(p1)
players.append(p2)

done = False
while not done:
    for event in pygame.event.get():  # gets all event in last tick
        if event.type == pygame.QUIT:
            done = True
        elif event.type == pygame.KEYDOWN:
            # === Player 1 === #
            if event.key == pygame.K_w:
                p1.dx = 0
                p1.dy = -1
            elif event.key == pygame.K_s:
                p1.dx = 0
                p1.dy = 1
            elif event.key == pygame.K_a:
                p1.dx = -1
                p1.dy = 0
            elif event.key == pygame.K_d:
                p1.dx = 1
                p1.dy = 0
            # === Player 2 === #
            if event.key == pygame.K_UP:
                p2.dx = 0
                p2.dy = -1
            elif event.key == pygame.K_DOWN:
                p2.dx = 0
                p2.dy = 1
            elif event.key == pygame.K_LEFT:
                p2.dx = -1
                p2.dy = 0
            elif event.key == pygame.K_RIGHT:
                p2.dx = 1
                p2.dy = 0
    p1.draw()
    p1.move()
    p2.draw()
    p2.move()
     # Trying to detect collision with one player and another player's path
    for rect in tron_path_1:
        if p2.player_rect.colliderect(rect):
            print("Player 1 Wins!")
            sys.exit()
        
    for rect in tron_path_2:
        if p1.player_rect.colliderect(rect):
            print("Player 2 Wins!")
            sys.exit()

    pygame.display.update()

pygame.quit()

Answer 1

您可以在 tron_path_1 中添加 p1 的碰撞条件，但这会立即结束游戏，因为矩形会与自身发生碰撞。所以你可以做的就是把它和其他两个循环一起添加

for rect in tron_path_1[:-10]:
    if p1.player_rect.colliderect(rect):
        print("Player 2 Wins!")
        sys.exit()

for rect in tron_path_2[:-10]:
    if p2.player_rect.colliderect(rect):
        print("Player 1 Wins!")
        sys.exit()

它的作用是检查与原始循环中相同的碰撞条件，但不考虑路径的最后 10 个矩形。
一个额外的 time.sleep(0.02)在 pygame.display.update() 之后添加稍微放慢游戏速度，以​​免在程序启动时 tron 角色全速奔跑。所以必须导入一个附加模块。因此添加 import time在代码的开头。