python - matlibplot中两个向量之间的填充区域

Question

以下代码计算以下向量:
方向矢量 (红色) 和 两个向量(蓝调)这是通过将红色矢量旋转 60 度时钟和逆时针而产生的。

import matplotlib.pyplot as plt
import numpy as np


def Visualize(orienVector,vector1,vector2):
 # Create figure and subplot
 fig = plt.figure()
 ax = fig.add_subplot(1, 1, 1)

 # Plot data points
 #ax.scatter(vector1[0], vector1[1], color='blue')
 #ax.scatter(vector2[0], vector2[1], color='orange')

 # Set limits for x and y axes
 plt.xlim(-1, 1)
 plt.ylim(-1, 1)

 # ===== Important bits start here =====

 # Set properties of spines
 ax.spines['top'].set_color('none')
 ax.spines['left'].set_position('zero')
 ax.spines['right'].set_color('none')
 ax.spines['bottom'].set_position('zero')

 # Set axis tick positions
 ax.xaxis.set_ticks_position('bottom')
 ax.yaxis.set_ticks_position('left')

 # Set specific tick locations
 ax.set_xticks([-10,-5, 0, 5 , 10])
 ax.set_yticks([-10,-5, 0, 5 , 10])

 # ===== End Of Important Bits =====

 # Draw arrows
 ax.arrow(0, 0 , vector1[0][0], vector1[1][0], 
    head_width=0.03, 
    head_length=0.1, 
    lw=1, 
    fc='blue', 
    ec='blue', 
    length_includes_head=True)
    
 ax.arrow(0, 0 , vector2[0][0], vector2[1][0], 
    head_width=0.03, 
    head_length=0.1, 
    lw=1, 
    fc='blue', 
    ec='blue', 
    length_includes_head=True)

 ax.arrow(0, 0 , orienVector[0][0], orienVector[1][0], 
    head_width=0.03, 
    head_length=0.1, 
    lw=2, 
    fc='red', 
    ec='red', 
    length_includes_head=True)

 plt.show()

# rotation matrix clockwise
def rotMatrixClockWise(angle):
 c, s = np.cos(angle), np.sin(angle)
 R = np.array([[c, -s], [s, c]])
 return R 

# rotation matrix clockwise
def rotMatrixCounterClockWise(angle):
 c, s = np.cos(angle), np.sin(angle)
 R = np.array([[c, s], [-s, c]])
 return R  

# center of the poit of interests POIS
POI_X = [10,12,15,17,20,50]
POI_Y = [20,30,25,22,19,35]

# position of the pedestrian 
pedPostion = np.array([[3],[4]])

# range of the horisontal angel view
spanningAngle = np.radians(60)

# calculate the cone 
for angle in range(0,360,5):
 
    
 # calculating the component of orientation vector V0, where the length |V0| = 1 
 x0 = 5*np.cos(np.radians(angle))
 y0 = 5*np.sin(np.radians(angle)) 
 v0 = np.array([[x0],[y0]])
 
 v1 = rotMatrixCounterClockWise(spanningAngle).dot(v0) 
 v2 = rotMatrixClockWise(spanningAngle).dot(v0) 


 Visualize(v0,v1,v2)

这个向量的输出看起来像

我正在尝试填充蓝色向量之间的区域以获得如下所示的锥体:

圆锥头 (0,0) 与圆弧之间的距离始终为 5
但是，我无法让它工作。我是 Matlibplot 的新手

Answer 1

也许不完全是你想要的，但你可以在向量之间创建一个楔子。拟合椭圆并填充其间的坐标会更合适。这是楔形的示例。

import matplotlib.pyplot as plt, numpy as np
from matplotlib import patches
v1 = np.array((1, 2))
v2 = np.array((1, -2))
base = np.array((0, 0))
theta1 = np.rad2deg(np.arctan(v1[1] / v1[0]))
theta2 = np.rad2deg(np.arctan(v2[1] / v2[0]))

fig, ax = plt.subplots()

a, b = theta1, theta2 
if b > a:
   a, b = b, a
artist = patches.Arc(base, 
            width = 1,
            height = 1, 
            theta1 = a, 
            theta2 = b,
            color = 'green')
ax.arrow(*base,  *v1, color = 'black')
ax.arrow(*base,  *v2, color = 'black')
ax.arrow(*base, *(v2 + v1), color = 'red')
wedge = patches.Wedge(base, 
            r = 1,
            width = 1, 
            theta1 = theta2, 
            theta2 = theta1,
            color = 'green')
ax.add_patch(wedge)

fig.show()