r - 如何使用for循环绘制ggplot？

Question

有什么有效的方法可以使用 for 循环绘制 ggplot 吗？如何正则表示将放入ggplot函数中的冒号？
例如我应该如何在代码中经常表达『satisfaction』和『Flight.Distance』？

ggplot(data = t1, aes(x = Flight.Distance))+
  geom_histogram(aes(y = ..density.., color =satisfaction, fill =satisfaction),  alpha = 0.4, position = "identity") +
  geom_density(aes(color = satisfaction), size =1)

我曾经使用以下代码成功过一次:

plot_data_column_2 = function (data, column1, column2) {
  ggplot(data, aes_string(x = column1, fill = column2)) +
    geom_bar(position = position_dodge())+
    guides(fill=guide_legend(title=sprintf('%s', column2)))+
    xlab(sprintf('%s', column2))
}

plot_data_column_2(data = data1, column1 = 'clus_res', column2 = 'Gender')

然而，我无法在 geom_histogram 上复制这种体验。我曾尝试过一些愚蠢的方法，但得到的输出却很糟糕

ggplot(data = t1, aes(x = Flight.Distance))+
  geom_histogram(aes(y = ..density.., color =t1[['satisfaction']] ,fill =t1[['satisfaction']]),  alpha = 0.4, position = "identity") +
  guides(fill=guide_legend(title='satisfaction'))+
  geom_density(aes(color = t1[['satisfaction']]), size =1)

因此，我尝试通过删除图例指南并稍后重新添加来解决此问题。但传奇已经一去不复返了

ggplot(data = t1, aes(x = t1[['Flight.Distance']]))+
  xlab('Flight.Distance')+
  geom_histogram(aes(y = ..density.., color =t1[['satisfaction']] ,fill =t1[['satisfaction']]),  alpha = 0.4, position = "identity") +
  theme(legend.position="none")+
  guides(col = guide_legend(ncol = 23))+
  geom_density(aes(color = t1[['satisfaction']]), size =1)

Answer 1

虽然可以使用 aes_string，但它是 "soft deprecated"一个更理想化的 tidyverse 方法是使用 "curly curly" {{ }} operator from tidyeval :

my_plot <- function(df, x_var, group_var) {
  df %>%
    ggplot(aes(x = {{x_var}},
               color = {{group_var}},
               fill  = {{group_var}},
               group = {{group_var}})) +
    geom_histogram(aes(y = ..density..),
                   alpha = 0.4, position = "identity") +
    geom_density(size = 1, fill = NA)
}

my_plot(mtcars, mpg, factor(am))