- html - 出于某种原因,IE8 对我的 Sass 文件中继承的 html5 CSS 不友好?
- JMeter 在响应断言中使用 span 标签的问题
- html - 在 :hover and :active? 上具有不同效果的 CSS 动画
- html - 相对于居中的 html 内容固定的 CSS 重复背景?
这是我想用 d3 js 实现的屏幕。
单击具有子圆圈的圆圈可以切换(折叠/展开)。
我试过下面的代码片段。我唯一无法实现的是,一旦父圈崩溃,我需要将子圈的所有链接转移到其父圈。任何领先都会很棒。
const data = {
name: "root",
children: [
{
name: "A",
children: [
{name: "A1", value: 7}, {name: "A2", value: 8}, {name: "A3", value: 9}, {name: "A4", value: 10}, {name: "A5", value: 10}
]
},
{
name: "B",
children: [
{name: "B1", value: 11}, {name: "B2", value: 7}, {name: "B3", value: 8},
]
},
{
name: "C",
value: 10
},
{
name: "D",
value: 10
},
{
name: "E",
value: 10
}
],
links: [{from: "A3", to: "C"}, {from: "A2", to: "E"}, {from: "B1", to: "D"}, {from: "B2", to: "B3"}, {from: "B1", to: "C"}]
};
const findNode = (parent, name) => {
if (parent.name === name)
return parent;
if (parent.children) {
for (let child of parent.children) {
const found = findNode(child, name);
if (found) {
return found;
}
}
}
return null;
}
const svg = d3.select("svg");
const container = svg.append('g')
.attr('transform', 'translate(0,0)')
const onClickNode = (e, d) => {
e.stopPropagation();
e.preventDefault();
const node = findNode(data, d.data.name);
if(node.children && !node._children) {
node._children = node.children;
node.children = undefined;
node.value = 20;
updateGraph(data);
} else {
if (node._children && !node.children) {
node.children = node._children;
node._children = undefined;
node.value = undefined;
updateGraph(data);
}
}
}
const updateGraph = graphData => {
const pack = data => d3.pack()
.size([600, 600])
.padding(0)
(d3.hierarchy(data)
.sum(d => d.value * 3.5)
.sort((a, b) => b.value - a.value));
const root = pack(graphData);
const nodes = root.descendants().slice(1);
console.log('NODES: ', nodes);
const nodeElements = container
.selectAll("g.node")
.data(nodes, d => d.data.name);
const addedNodes = nodeElements.enter()
.append("g")
.classed('node', true)
.style('cursor', 'pointer')
.on('click', (e, d) => onClickNode(e, d));
addedNodes.append('circle')
.attr('stroke', 'black')
addedNodes.append("text")
.text(d => d.data.name)
.attr('text-anchor', 'middle')
.attr('alignment-baseline', 'middle')
.style('visibility', 'hidden')
.style('fill', 'black');
const mergedNodes = addedNodes.merge(nodeElements);
mergedNodes
.transition()
.duration(500)
.attr('transform', d => `translate(${d.x},${d.y})`);
mergedNodes.select('circle')
.attr("fill", d => d.children ? "#ffe0e0" : "#ffefef")
.transition()
.duration(1000)
.attr('r', d => d.value)
mergedNodes.select('text')
.attr('dy', d => d.children ? d.value + 10 : 0)
.transition()
.delay(1000)
.style('visibility', 'visible')
const exitedNodes = nodeElements.exit()
exitedNodes.select('circle')
.transition()
.duration(500)
.attr('r', 1);
exitedNodes.select('text')
.remove();
exitedNodes
.transition()
.duration(750)
.remove();
const linkPath = d => {
const from = nodes.find(n => n.data.name === d.from);
const to = nodes.find(n => n.data.name === d.to);
if (!from || !to)
return null;
const length = Math.hypot(from.x - to.x, from.y - to.y);
const fd = from.value / length;
const fx = from.x + (to.x - from.x) * fd;
const fy = from.y + (to.y - from.y) * fd;
const td = to.value / length;
const tx = to.x + (from.x - to.x) * td;
const ty = to.y + (from.y - to.y) * td;
return `M ${fx},${fy} L ${tx},${ty}`;
};
const linkElements = container.selectAll('path.link')
.data(data.links.filter(linkPath));
const addedLinks = linkElements.enter()
.append('path')
.classed('link', true)
.attr('marker-end', 'url(#arrowhead-to)')
.attr('marker-start', 'url(#arrowhead-from)');
addedLinks.merge(linkElements)
.transition()
.delay(750)
.attr('d', linkPath)
linkElements.exit().remove();
}
updateGraph(data);
text {
font-family: "Ubuntu";
font-size: 12px;
}
.link {
stroke: blue;
fill: none;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/6.7.0/d3.min.js"></script>
<svg width="600" height="600">
<defs>
<marker id="arrowhead-to" markerWidth="10" markerHeight="7"
refX="10" refY="3.5" orient="auto">
<polygon fill="blue" points="0 0, 10 3.5, 0 7" />
</marker>
<marker id="arrowhead-from" markerWidth="10" markerHeight="7"
refX="0" refY="3.5" orient="auto">
<polygon fill="blue" points="10 0, 0 3.5, 10 7" />
</marker>
</defs>
</svg>
最佳答案
替换折叠节点的链接:
const links = data.links.map(link => {
let from = nodes.find(n => n.data.name === link.from);
if (!from) {
const ancestors = findNodeAncestors(data, link.from);
for (let index = 1; !from && index < ancestors.length -1; index++) {
from = nodes.find(n => n.data.name === ancestors[index].name)
}
}
let to = nodes.find(n => n.data.name === link.to);
if (!to) {
const ancestors = findNodeAncestors(data, link.to);
for (let index = 1; !to && index < ancestors.length -1; index++) {
to = nodes.find(n => n.data.name === ancestors[index].name)
}
}
return {from, to};
});
这是
findNodeAncestors
的代码:
const findNodeAncestors = (parent, name) => {
if (parent.name === name)
return [parent];
const children = parent.children || parent._children;
if (children) {
for (let child of children) {
const found = findNodeAncestors(child, name);
if (found) {
return [...found, parent];
}
}
}
return null;
}
const data = {
name: "root",
children: [
{
name: "A",
children: [
{name: "A1", value: 7}, {name: "A2", value: 8}, {name: "A3", value: 9}, {name: "A4", value: 10}, {name: "A5", value: 10}
]
},
{
name: "B",
children: [
{name: "B1", value: 11}, {name: "B2", value: 7}, {name: "B3", value: 8},
]
},
{
name: "C",
value: 10
},
{
name: "D",
value: 10
},
{
name: "E",
value: 10
}
],
links: [{from: "A3", to: "C"}, {from: "A2", to: "E"}, {from: "B1", to: "D"}, {from: "B2", to: "B3"}, {from: "B1", to: "C"}, {from: "B1", to: "A5"}]
};
const findNode = (parent, name) => {
if (parent.name === name)
return parent;
if (parent.children) {
for (let child of parent.children) {
const found = findNode(child, name);
if (found) {
return found;
}
}
}
return null;
}
const findNodeAncestors = (parent, name) => {
if (parent.name === name)
return [parent];
const children = parent.children || parent._children;
if (children) {
for (let child of children) {
const found = findNodeAncestors(child, name);
//console.log('FOUND: ', found);
if (found) {
return [...found, parent];
}
}
}
return null;
}
const svg = d3.select("svg");
const container = svg.append('g')
.attr('transform', 'translate(0,0)')
const onClickNode = (e, d) => {
e.stopPropagation();
e.preventDefault();
const node = findNode(data, d.data.name);
if(node.children && !node._children) {
node._children = node.children;
node.children = undefined;
node.value = 20;
updateGraph(data);
} else {
if (node._children && !node.children) {
node.children = node._children;
node._children = undefined;
node.value = undefined;
updateGraph(data);
}
}
}
const updateGraph = graphData => {
const pack = data => d3.pack()
.size([600, 600])
.padding(0)
(d3.hierarchy(data)
.sum(d => d.value * 3.5)
.sort((a, b) => b.value - a.value));
const root = pack(graphData);
const nodes = root.descendants().slice(1);
const nodeElements = container
.selectAll("g.node")
.data(nodes, d => d.data.name);
const addedNodes = nodeElements.enter()
.append("g")
.classed('node', true)
.style('cursor', 'pointer')
.on('click', (e, d) => onClickNode(e, d));
addedNodes.append('circle')
.attr('stroke', 'black')
addedNodes.append("text")
.text(d => d.data.name)
.attr('text-anchor', 'middle')
.attr('alignment-baseline', 'middle')
.style('visibility', 'hidden')
.style('fill', 'black');
const mergedNodes = addedNodes.merge(nodeElements);
mergedNodes
.transition()
.duration(500)
.attr('transform', d => `translate(${d.x},${d.y})`);
mergedNodes.select('circle')
.attr("fill", d => d.children ? "#ffe0e0" : "#ffefef")
.transition()
.duration(1000)
.attr('r', d => d.value)
mergedNodes.select('text')
.attr('dy', d => d.children ? d.value + 10 : 0)
.transition()
.delay(1000)
.style('visibility', 'visible')
const exitedNodes = nodeElements.exit()
exitedNodes.select('circle')
.transition()
.duration(500)
.attr('r', 1);
exitedNodes.select('text')
.remove();
exitedNodes
.transition()
.duration(750)
.remove();
const linkPath = d => {
const length = Math.hypot(d.from.x - d.to.x, d.from.y - d.to.y);
const fd = d.from.value / length;
const fx = d.from.x + (d.to.x - d.from.x) * fd;
const fy = d.from.y + (d.to.y - d.from.y) * fd;
const td = d.to.value / length;
const tx = d.to.x + (d.from.x - d.to.x) * td;
const ty = d.to.y + (d.from.y - d.to.y) * td;
return `M ${fx},${fy} L ${tx},${ty}`;
};
const links = data.links.map(link => {
let from = nodes.find(n => n.data.name === link.from);
if (!from) {
const ancestors = findNodeAncestors(data, link.from);
for (let index = 1; !from && index < ancestors.length -1; index++) {
from = nodes.find(n => n.data.name === ancestors[index].name)
}
}
let to = nodes.find(n => n.data.name === link.to);
if (!to) {
const ancestors = findNodeAncestors(data, link.to);
for (let index = 1; !to && index < ancestors.length -1; index++) {
to = nodes.find(n => n.data.name === ancestors[index].name)
}
}
return {from, to};
});
const linkElements = container.selectAll('path.link')
.data(links.filter(l => l.from && l.to));
const addedLinks = linkElements.enter()
.append('path')
.classed('link', true)
.attr('marker-end', 'url(#arrowhead-to)')
.attr('marker-start', 'url(#arrowhead-from)');
addedLinks.merge(linkElements)
.style('visibility', 'hidden')
.transition()
.delay(750)
.attr('d', linkPath)
.style('visibility', 'visible')
linkElements.exit().remove();
}
updateGraph(data);
text {
font-family: "Ubuntu";
font-size: 12px;
}
.link {
stroke: blue;
fill: none;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/6.7.0/d3.min.js"></script>
<svg width="600" height="600">
<defs>
<marker id="arrowhead-to" markerWidth="10" markerHeight="7"
refX="10" refY="3.5" orient="auto">
<polygon fill="blue" points="0 0, 10 3.5, 0 7" />
</marker>
<marker id="arrowhead-from" markerWidth="10" markerHeight="7"
refX="0" refY="3.5" orient="auto">
<polygon fill="blue" points="10 0, 0 3.5, 10 7" />
</marker>
</defs>
</svg>
关于javascript - 一旦父节点在 d3 图中折叠,需要将子节点的链接转移到父节点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/67633143/
我需要将文本放在 中在一个 Div 中,在另一个 Div 中,在另一个 Div 中。所以这是它的样子: #document Change PIN
奇怪的事情发生了。 我有一个基本的 html 代码。 html,头部, body 。(因为我收到了一些反对票,这里是完整的代码) 这是我的CSS: html { backgroun
我正在尝试将 Assets 中的一组图像加载到 UICollectionview 中存在的 ImageView 中,但每当我运行应用程序时它都会显示错误。而且也没有显示图像。 我在ViewDidLoa
我需要根据带参数的 perl 脚本的输出更改一些环境变量。在 tcsh 中,我可以使用别名命令来评估 perl 脚本的输出。 tcsh: alias setsdk 'eval `/localhome/
我使用 Windows 身份验证创建了一个新的 Blazor(服务器端)应用程序,并使用 IIS Express 运行它。它将显示一条消息“Hello Domain\User!”来自右上方的以下 Ra
这是我的方法 void login(Event event);我想知道 Kotlin 中应该如何 最佳答案 在 Kotlin 中通配符运算符是 * 。它指示编译器它是未知的,但一旦知道,就不会有其他类
看下面的代码 for story in book if story.title.length < 140 - var story
我正在尝试用 C 语言学习字符串处理。我写了一个程序,它存储了一些音乐轨道,并帮助用户检查他/她想到的歌曲是否存在于存储的轨道中。这是通过要求用户输入一串字符来完成的。然后程序使用 strstr()
我正在学习 sscanf 并遇到如下格式字符串: sscanf("%[^:]:%[^*=]%*[*=]%n",a,b,&c); 我理解 %[^:] 部分意味着扫描直到遇到 ':' 并将其分配给 a。:
def char_check(x,y): if (str(x) in y or x.find(y) > -1) or (str(y) in x or y.find(x) > -1):
我有一种情况,我想将文本文件中的现有行包含到一个新 block 中。 line 1 line 2 line in block line 3 line 4 应该变成 line 1 line 2 line
我有一个新项目,我正在尝试设置 Django 调试工具栏。首先,我尝试了快速设置,它只涉及将 'debug_toolbar' 添加到我的已安装应用程序列表中。有了这个,当我转到我的根 URL 时,调试
在 Matlab 中,如果我有一个函数 f,例如签名是 f(a,b,c),我可以创建一个只有一个变量 b 的函数,它将使用固定的 a=a1 和 c=c1 调用 f: g = @(b) f(a1, b,
我不明白为什么 ForEach 中的元素之间有多余的垂直间距在 VStack 里面在 ScrollView 里面使用 GeometryReader 时渲染自定义水平分隔线。 Scrol
我想知道,是否有关于何时使用 session 和 cookie 的指南或最佳实践? 什么应该和什么不应该存储在其中?谢谢! 最佳答案 这些文档很好地了解了 session cookie 的安全问题以及
我在 scipy/numpy 中有一个 Nx3 矩阵,我想用它制作一个 3 维条形图,其中 X 轴和 Y 轴由矩阵的第一列和第二列的值、高度确定每个条形的 是矩阵中的第三列,条形的数量由 N 确定。
假设我用两种不同的方式初始化信号量 sem_init(&randomsem,0,1) sem_init(&randomsem,0,0) 现在, sem_wait(&randomsem) 在这两种情况下
我怀疑该值如何存储在“WORD”中,因为 PStr 包含实际输出。? 既然Pstr中存储的是小写到大写的字母,那么在printf中如何将其给出为“WORD”。有人可以吗?解释一下? #include
我有一个 3x3 数组: var my_array = [[0,1,2], [3,4,5], [6,7,8]]; 并想获得它的第一个 2
我意识到您可以使用如下方式轻松检查焦点: var hasFocus = true; $(window).blur(function(){ hasFocus = false; }); $(win
我是一名优秀的程序员,十分优秀!