asp.net-core-2.0 - 如何从Core 2 Razor页面ViewModel处理程序返回部分 View

Question

在Asp.Net MVC中，您可以通过执行以下操作轻松返回部分 View :
return PartialView("ModelName", Model);
如何在RazorPage ViewModel处理程序上完成此操作？

Answer 1

我想通了。它不像在MVC中那样直接。您必须创建一个空的ViewDataDictionary()，然后将其Model属性设置为该部分的填充模型。

查看模型/处理程序

public async Task<IActionResult> OnGetAsyncUpdateSearchResults(DateTime startDate, DateTime endDate, string selectedTypes)
{
    int[] types = selectedTypes.Split(",").Select(x => int.Parse(x)).ToArray();

    var inventory = await _itemService.GetFiltered(types, null, null, null, null, null, null, startDate, endDate.ToUniversalTime(), null, null, null, null, null, null, null);

    if (inventory != null)
    {
        SearchResultsGridPartialModel = new SearchResultsGridPartialModel();
        SearchResultsGridPartialModel.TotalCount = inventory.TotalCount;
        SearchResultsGridPartialModel.TotalPages = inventory.TotalPages;
        SearchResultsGridPartialModel.PageNumber = inventory.PageNumber;
        SearchResultsGridPartialModel.Items = inventory.Items;
    }

    var myViewData = new ViewDataDictionary(new Microsoft.AspNetCore.Mvc.ModelBinding.EmptyModelMetadataProvider(), new Microsoft.AspNetCore.Mvc.ModelBinding.ModelStateDictionary()) { { "SearchResultsGridPartialModel", SearchResultsGridPartialModel } };
    myViewData.Model = SearchResultsGridPartialModel;

    PartialViewResult result = new PartialViewResult()
    {
        ViewName = "SearchResultsGridPartial",
        ViewData = myViewData,
    };

    return result;
}

我现在可以通过ajax GET调用此处理程序，并使其返回部分的HTML。然后，我可以按预期设置部分的 div和部分刷新。

这是我正在进行的AJAX调用:

var jsonData = { "startDate": startDate, "endDate": endDate, "selectedTypes": selectedTypesAsString };

$.ajax({
    type: 'GET',
    url: "searchresults/?handler=AsyncUpdateSearchResults",
    beforeSend: function (xhr) {
        xhr.setRequestHeader("XSRF-TOKEN", $('input:hidden[name="__RequestVerificationToken"]').val());
    },
    contentType: 'application/json; charset=utf-8"',
    data: jsonData,
    success: function (result) {
        $("#searchResultsGrid").html(result);
    },
    error: function (error) {
        console.log(error);
    }
});