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python - 不确定如何在元组列表中引用元组中的元素

转载 作者:行者123 更新时间:2023-12-04 07:20:27 25 4
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我正在尝试完成一个初学者任务,该任务需要在列表中引用元组中的元素,该列表使用 for 循环和条件根据元组中的值输出两种类型的字符串之一。

Using a for loop and an if statement, go through vacc_counties and print out a message for those counties that have a higher than 30% vaccination rate.

Add another loop that prints out a message for every county, but prints different messages if the rate is above or below 30.

Example:
Benton County is doing ok, with a rate of 41.4%
Fulton County is doing less ok, with a rate of 22.1%


这是元组列表,后面是我自己的代码:
vacc_counties = [('Pulaski', 42.7), ('Benton', 41.4), ('Fulton', 22.1), ('Miller', 9.6),
('Mississippi', 29.4), ('Scotty County', 28.1)]

for tuple in vacc_counties:
for element in tuple:
if [1] < 30:
print(f"{vacc_counties[0]}is doing ok, with a rate of" [1]"%")
else [1] n > 30:
print(f"{vacc_counties[0]}is doing ok, with a rate of" [1]"%")

最佳答案

评论:

  • 不要对变量名使用保留字,例如使用 tpl而不是 tuple
  • 删除 for element in tuple:循环
  • 要访问元组的第二个元素,请使用 tpl[1]而不是 [1]
  • 使用 elif相反 else

  • 更正的代码:
    vacc_counties = [
    ("Pulaski", 42.7),
    ("Benton", 41.4),
    ("Fulton", 22.1),
    ("Miller", 9.6),
    ("Mississippi", 29.4),
    ("Scotty County", 28.1),
    ]

    for tpl in vacc_counties:
    if tpl[1] < 30:
    print(f"{tpl[0]} is doing less ok, with a rate of {tpl[1]}%")
    elif tpl[1] >= 30:
    print(f"{tpl[0]} is doing ok, with a rate of {tpl[1]}%")
    打印:
    Pulaski is doing ok, with a rate of 42.7%
    Benton is doing ok, with a rate of 41.4%
    Fulton is doing less ok, with a rate of 22.1%
    Miller is doing less ok, with a rate of 9.6%
    Mississippi is doing less ok, with a rate of 29.4%
    Scotty County is doing less ok, with a rate of 28.1%

    关于python - 不确定如何在元组列表中引用元组中的元素,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/68537230/

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