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python - Django表单初始化方法失败

转载 作者:行者123 更新时间:2023-12-04 07:15:36 26 4
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我有一个用户添加表单 View ,它要求提供信息并将新用户保存到数据库中。当我尝试保存新的用户记录时,出现以下错误。

TypeError at /user/add/
__init__() missing 1 required positional argument: 'customer'
Request Method: GET
Request URL: http://localhost:8000/user/add/
Django Version: 3.0.5
Exception Type: TypeError
Exception Value:
__init__() missing 1 required positional argument: 'customer'
Exception Location: D:\Job Documents\DDS\AuthenticationProject\env\lib\site-packages\django\views\generic\edit.py in get_form, line 33
Python Executable: D:\Job Documents\DDS\AuthenticationProject\env\Scripts\python.exe
Python Version: 3.9.0
Python Path:
['D:\\Job Documents\\DDS\\AuthenticationProject\\auth',
'C:\\Users\\bratca\\AppData\\Local\\Programs\\Python\\Python39\\python39.zip',
'C:\\Users\\bratca\\AppData\\Local\\Programs\\Python\\Python39\\DLLs',
'C:\\Users\\bratca\\AppData\\Local\\Programs\\Python\\Python39\\lib',
'C:\\Users\\bratca\\AppData\\Local\\Programs\\Python\\Python39',
'D:\\Job Documents\\DDS\\AuthenticationProject\\env',
'D:\\Job Documents\\DDS\\AuthenticationProject\\env\\lib\\site-packages']
Server time: Sun, 15 Aug 2021 08:05:30 +0000
我使用客户对象来区分用户,因此我希望表单知道它是由谁填写的,这样新创建的用户将拥有与创建者相同的客户对象。
此错误并未准确显示代码中我的错误在哪里。相反,它在实际的 django 代码中显示了一些错误,即我正在使用的通用内容。
class AddUserFormView(FormView):
form_class = TbUserAddForm
template_name = 'users/add_user_modal.html'
success_message = "Account has been created! The user is able to log in."

def post(self, request):
form = self.form_class(customer=request.user.customer,
data=request.POST, files=request.FILES)
if form.is_valid():
user_face_img_md5 = Image.open(
request.FILES['user_face_img_md5'].file)
user_head_img_md5 = Image.open(
request.FILES['user_head_img_md5'].file)
obj = form.save(commit=False)
response = addUserApi(obj.__dict__,
user_face_img_md5,
user_head_img_md5)
print(f"Request Response [Add User] --> {response.text}")
# if response.text['status'] != 45001:
# messages.error(f'Something went wrong. {response.text}')
return redirect('add-user')
else:
messages.error(request, form.errors)
return redirect('add-user')
class TbUserAddForm(CustomUserCreationForm):
email = forms.EmailField()
user_head_img_md5 = forms.ImageField(label='Avatar', required=True)
user_face_img_md5 = forms.ImageField(
label='Face Recognition Image', required=True)

def __init__(self, customer, *args, **kwargs):
super().__init__(*args, **kwargs)
print(f'USER ADD FORM CUSTOMER -> {customer}')
self.customer = customer
if self.customer:
self.fields['role'].queryset = TbRole.objects.all().filter(
customer=self.customer)
self.fields['department'].queryset = TbDepartment.objects.all().filter(
customer=self.customer)

class Meta:
model = TbUser
fields = [...]

path('add/', views.AddUserFormView.as_view(), name='add-user'),

用户不是由 django 保存的,而是由 addUserApi() 保存的向另一台服务器发送请求。因此有时会因为 addUserApi 工作而创建用户。但是抛出了同样的错误。

最佳答案

您应该覆盖 .get_form_kwargs(…) method [Django-doc]将数据传递到您在 GET 和 POST 请求中构建的表单:

from django.contrib.auth.mixins import LoginRequiredMixin
from django.contrib.messages.views import SuccessMessageMixin
from django.urls import reverse_lazy

class AddUserFormView(LoginRequiredMixin, SuccessMessageMixin, FormView):
form_class = TbUserAddForm
template_name = 'users/add_user_modal.html'
success_message = 'Account has been created! The user is able to log in.'
success_url = reverse_lazy('add-user')

def get_form_kwargs(self):
formkw = super().get_form_kwargs()
formkw['customer'] = self.request.user.customer
return formkw

def form_valid(self, form):
user_face_img_md5 = Image.open(self.request.FILES['user_face_img_md5'].file)
user_head_img_md5 = Image.open(self.request.FILES['user_head_img_md5'].file)
obj = form.save(commit=False)
response = addUserApi(
obj.__dict__,
user_face_img_md5,
user_head_img_md5
)
print(f'Request Response [Add User] --> {response.text}')
return super().form_valid(form)
通常不会覆盖 post和/或 get基于类的 View 的方法,因为它包含大部分样板代码。在这里覆盖 .form_valid(…) method [Django-doc] 可能就足够了指定在表单有效的情况下应该发生什么。

Note: You can limit views to a class-based view to authenticated users with theLoginRequiredMixin mixin [Django-doc].



Note: One can make use of the SuccessMessageMixin mixinto a view to add a success message in case the form was valid.

关于python - Django表单初始化方法失败,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/68789803/

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