.net - 使用 linq to xml 读取 CDATA

Question

我有以下 xml 文件，似乎无法弄清楚如何获取元素中的值(埋在 CDATA 中)。我正在尝试为此使用 linq to xml。如果有人知道如何将其转换为“产品”对象(假设我们有一个产品对象，其属性与元素名称相同)。提前致谢。

鲍勃

<CNETResponse realm="cnet" version="1.0" xmlns="http://api.cnet.com/rest/v1.0/ns" xmlns:xlink="http://www.w3.org/1999/xlink">
<TechProduct id="33517677">
    <Name><![CDATA[Nikon CoolPix L20 (deep red)]]></Name>
    <Topic id="1670"></Topic>
    <ImageURL width="60"><![CDATA[http://i.i.com.com/cnwk.1d/sc/33517677-2-60-0.gif]]></ImageURL>
</TechProduct>
</CNETResponse>

Answer 1

问题是命名空间 - 例如，类似于:

XNamespace ns = "http://api.cnet.com/rest/v1.0/ns";
XElement techProd = doc.Root.Element(ns + "TechProduct");

Product product = new Product {
    Id = (int)techProd.Attribute("id"),
    Name = techProd.Element(ns + "Name").Value,
    Topic = techProd.Element(ns + "Topic").Value,
    TopicId = (int)techProd.Element(ns + "Topic").Attribute("id"),
    ImageUrl = techProd.Element(ns + "ImageURL").Value,
    ImageWidth = (int)techProd.Element(ns + "ImageURL").Attribute("width"),
};

您可能还喜欢 XmlSerializer - 就像是:

XmlSerializer ser = new XmlSerializer(typeof(CnetResponse));
CnetResponse response = (CnetResponse)ser.Deserialize(new StringReader(xml));
TechProduct product = response.TechProduct;

使用类定义，例如:

[Serializable, XmlRoot("CNETResponse", Namespace = CnetResponse.Namespace)]
public class CnetResponse {
    public const string Namespace = "http://api.cnet.com/rest/v1.0/ns";
    public TechProduct TechProduct { get; set; }
}
[Serializable, XmlType(Namespace = CnetResponse.Namespace)]
public class TechProduct
{
    [XmlAttribute("id")]
    public int Id { get; set; }
    public string Name {get;set;}
    public Topic Topic { get; set; }
    [XmlElement("ImageURL")]
    public Image Image { get; set; }        
}
[Serializable, XmlType(Namespace = CnetResponse.Namespace)]
public class Topic {
    [XmlAttribute("id")]
    public int Id { get; set; }
    [XmlText]
    public string Text {get;set;}
}
[Serializable, XmlType(Namespace = CnetResponse.Namespace)]
public class Image {
    [XmlAttribute("width")]
    public int Width { get; set; }
    [XmlText]
    public string Url {get;set;}
}

或者，只需通过 xsd.exe 运行 xml使 C# 代码适合:

xsd foo.xml
xsd foo.xsd /classes