ruby-on-rails-3 - rails 如果其他检查失败则救援

Question

我的 Controller 中有 2 个用于查找用户的方法(注意 enabled_only 范围):

before_filter :find_user, :only => :show
before_filter :find_any_user, :only => [:edit, :update, :destroy]

def find_user
  @user = User.enabled_only.find(params[:id])
rescue ActiveRecord::RecordNotFound
  flash[:alert] = "The user you were looking for could not be found"
  redirect_to root_path
end

def find_any_user
  @user = User.find(params[:id])
rescue ActiveRecord::RecordNotFound
  flash[:alert] = "The user you were looking for could not be found"
  redirect_to root_path
end

当然，这些可以合并成一种检查是否 :action == 'show' 的方法。但我无法通过救援来捕捉错误。我尝试了类似以下的操作，但没有奏效:

before_filter :find_user, :only => [:show, :edit, :update, :destroy]

def find_user
  @user = if :action == 'show'
    User.enabled_only.find(params[:id])
  else
    User.find(params[:id])
  end
rescue ActiveRecord::RecordNotFound
  flash[:alert] = "The user you were looking for could not be found"
  redirect_to root_path
end

请告知如何做到这一点。

谢谢

Answer 1

您需要将要“保护”的代码包装在 begin 之间和一个 rescue

before_filter :find_user, :only => [:show, :edit, :update, :destroy]

def find_user
  begin
    @user = if :action == 'show'
      User.enabled_only.find(params[:id])
    else
      User.find(params[:id])
    end
  rescue ActiveRecord::RecordNotFound
    flash[:alert] = "The user you were looking for could not be found"
    redirect_to root_path
  end
end

顺便说一下你的测试 :action == 'show'永远不可能是真的。 :action是一个符号，其值为 :action ，它的值永远不会改变，与 'show' 相同，它的值永远不会改变。我不确定实现这一目标的最佳方法是什么，但您可以这样做，但您可以这样做 if params[:action] == "show"