Drupal 对数据库执行查询

Question

我希望从我的 drupal 数据库中检索一些 nid。我有一个想要运行的查询。

  SELECT node.nid AS projectnid
            FROM node node
            INNER JOIN content_type_project node_data_field_project_client ON node.vid = node_data_field_project_client.vid
            WHERE node_data_field_project_client.field_project_client_nid = (SELECT node_data_field_profile_company.field_profile_company_nid AS company_nid
            FROM node node  LEFT JOIN content_type_profile node_data_field_profile_company ON node.vid = node_data_field_profile_company.vid WHERE node.nid = 218)

我正在使用以下方法调用查询:

$query =
        "
            SELECT node.nid AS projectnid
            FROM node node
            INNER JOIN content_type_project node_data_field_project_client ON node.vid = node_data_field_project_client.vid
            WHERE node_data_field_project_client.field_project_client_nid = (SELECT node_data_field_profile_company.field_profile_company_nid AS company_nid
            FROM node node  LEFT JOIN content_type_profile node_data_field_profile_company ON node.vid = node_data_field_profile_company.vid WHERE node.nid = 218)
        ";
$result = db_query($query);
dsm($result);

dsm 给了我一个空对象。当我直接运行 SQL 时，我会得到一个结果。

所以我的问题是如何让 db_query 将所有结果作为对象返回(我真的不介意是对象还是数组)。

(该 SQL 是通过查看 View 的查询输出创建的。)

这是对问题的跟进: Drupal Views Relationships and Arguments

I have a Person content type. It has a node reference field of a company which is also a content type. I then have a content type called Project. A project has a node reference to a company content type. I want to list all the projects related to a person id (nid)id (nid)

Answer 1

以下工作:

$query =
        "
            SELECT node.nid AS projectnid
            FROM node node
            INNER JOIN content_type_project node_data_field_project_client ON node.vid = node_data_field_project_client.vid
            WHERE node_data_field_project_client.field_project_client_nid = (SELECT node_data_field_profile_company.field_profile_company_nid AS company_nid
            FROM node node  LEFT JOIN content_type_profile node_data_field_profile_company ON node.vid = node_data_field_profile_company.vid WHERE node.nid = 218)
        ";
$results = db_query($query);
while ($result = db_result($results)) {
    dsm($result);
}

您需要使用 db_result() 来获取结果。使用 http://drupal.org/node/259432#comment-846946 解决了这个问题