php设计问题

Question

我有以下类(class):

class Apiconnect {

  const URL = 'https://someurl.com/api.php';
  const USERNAME = 'user';
  const PASSWORD = 'pass';

/**
*
* @param <array> $postFields
* @return SimpleXMLElement
* @desc this connects but also sends and retrieves the information returned in XML
*/

 public function Apiconnect($postFields)
 {
   $postFields["username"] = self::USERNAME;
   $postFields["password"] = md5(self::PASSWORD);
   $postFields["responsetype"] = 'xml';
   $ch = curl_init();
   curl_setopt($ch, CURLOPT_URL, self::URL);
   curl_setopt($ch, CURLOPT_POST, 1);
   curl_setopt($ch, CURLOPT_TIMEOUT, 100);
   curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 
   curl_setopt($ch, CURLOPT_POSTFIELDS, $postFields);
   $data = curl_exec($ch);
   curl_close($ch);
   $xml = new SimpleXMLElement($data);
   if($xml->result == "success")
   {
     return $xml;
   }
   else
   {  
    return $xml->message;
   }
 }
} 

现在我想在将使用它的其他类的其他方法上使用这个连接类。

所以，我正在考虑做一个类(不确定抽象在这里是否合适)，如下所示:

abstract class ApiSomething
{
  protected $_connection;
  protected $_postFields = array();

  /**
   * @desc - Composition.
   */

  public function __construct()
  {
     require_once("apiconnect.php");
     $this->_connection = new Apiconnect($this->_postFields);
  }

  public function getStuff()
  {

   //this is the necessary field that needs to be send. 
   //Containing the action that the API should perform.
   $this->_postFields["action"] = "dosomething";
   ...
   }

} 

我需要在 getStuff() 方法上使用 $_connection 属性，以便将“操作”发送到 API 中。然而，不确定如何实现。

请问有什么帮助吗？

Answer 1

为什么不扩展你的对象而不是包含一些东西。 APIConnect 应该是抽象类，API 应该扩展它。

abstract class ApiConnect {
    protected $_something;
    protected $_something2;
    protected $_curlResource;
    function __construct($param1){
        /* do curl setup here and save it to $this->_curlResource */
    }
}

class ApiSomething extends ApiConnect {
    protected $_paramForBase;
    function __construct(){
        super($this->_paramForBase);
        echo "Var from base: ".parent::_something;
        /* do more things with curl here, through parent::_curlResource */
    }

    function setParamsForCurlCall(){
        /* add curl parameters with curl here, through parent::_curlResource */
    }

    function execCurl(){
        /* do your final curl call here */
    }
}

然后你可以用你的抽象类做任何你想做的事情，你可以用 API 来拥有基类的所有控制逻辑。当然，如果您要在多个类中扩展 ApiConnect，您只想这样做。