c - 这是如何使用scanf接受多字串的？

Question

printf("enter the string");
    scanf("%[^\t\n]s",str); 

//abv 代码如何在不使用 get 且仅使用 scanf 的情况下接受多字串

Answer 1

[ Matches a nonempty sequence of characters from the specified set of accepted characters; the next pointer must be a pointer to char, and there must be enough room for all the characters in the string, plus a terminating null byte. The usual skip of leading white space is suppressed. The string is to be made up of characters in (or not in) a particular set; the set is defined by the characters between the open bracket [ character and a close bracket ] character. The set excludes those characters if the first character after the open bracket is a circumflex (^).

...

The string ends with the appearance of a character not in the (or, with a circumflex, in) set or when the field width runs out.

(Linux scanf(3) 联机帮助页。)

所以 scanf读取到第一个不是制表符 ( \t ) 或换行符 ( \n ) 的字符。它确实读取空格。