ruby-on-rails - Ruby on rails TypeError(无法将 Hash 转换为整数)

Question

我在 Controller 中有一个类作为客户端 API，它在不检查 organization_id 的情况下工作，organization_id 通过用户和成员链接到观察。

 def update
    @observation = Observation.find(params[:id])
    if params[:state] == 'submitted' && @observation.submit
      if @observation.source.source_type == 'registered'
        @user = User.find(id: @observation.source.source_identifier)
        @memberships = Membership.find(user_id: @user.id)
        if @memberships.present? &&@memberships.where("organization_id IS NOT NULL")
          @observation.approve
        end
      end

      render json: { createdAt: @observation.created_at }, status: 200
    else
      render nothing: true, status: 406
    end
  end

TypeError(无法将 Hash 转换为整数): app/controllers/api/client/v1/observations_controller.rb:106:in `update'这是行:

@user = User.find(id: @observation.source.source_identifier)

表结构:

  # create_table "sources", force: true do |t|
  #   t.string   "device_id"
  #   t.string   "source_type"
  #   t.string   "source_identifier"
  #   ...

  # create_table "users", force: true do |t|
  #     #   t.string   "email",                  default: "", null: false
  #   t.string   "encrypted_password",     default: "", null: false
  #    ...
  #   t.string   "first_name"
  #   t.string   "last_name"
  #   t.string   "phone"
  #   t.integer  "source_id"
  #   ...

  # create_table "memberships", force: true do |t|
  #   t.integer  "user_id"
  #   t.integer  "organization_id"
  #   t.datetime "verified_at"
  #   ...

Answer 1

假设您正在运行 Rails 4+，要按属性查找记录，只需使用此模式:

Model.find_by(attribute_name: attribute_value)

因此，在您的情况下:

@user = User.find_by(source_identifier: @observation.source.source_identifier)