asp.net - 如何在异步 Controller 中验证模型状态

Question

我正在尝试使用异步 Controller ，但无法弄清楚如何验证用户输入。

以下是我的 Controller 中定义的两个异步方法。我应该在 SearchAsync 方法或 SearchCompleted 方法中检查 ModelState.IsValid 吗？如果 SearchAsync 那么如何返回 View 结果，因为它的返回类型是 void。如果 SearchCompleted 那么该方法将如何知道 searchForm 参数。

[HttpPost]
[ValidateAntiForgeryToken]
public void SearchAsync(BusinessSearchForm searchForm)
{
    AsyncManager.OutstandingOperations.Increment();
    new Thread(() =>
    {
        var suggestions = _searchSvc.GetSuggestions(searchForm.BusinessName, searchForm.StreetAddress, searchForm.City, searchForm.PostalCode);
        AsyncManager.Parameters["suggestions"] = suggestions;                   
        AsyncManager.OutstandingOperations.Decrement();
    }).Start();
}

public ActionResult SearchCompleted(IEnumerable<BusinessSuggestionBase> suggestions)
{
    return View(suggestions);
}

Answer 1

以下似乎对我有用。我最终在这两种方法中都检查了模型状态。将初始模型作为参数添加到已完成的方法中。 Asp.net Mvc 似乎在两种方法之间保持模型状态

    [HttpPost]
    [ValidateAntiForgeryToken]
    public void SearchAsync(BusinessSearchForm searchForm)
    {
        if (ModelState.IsValid)
        {
            AsyncManager.OutstandingOperations.Increment();
            new Thread(() =>
            {
                if (ModelState.IsValid)
                {
                    var suggestions = _searchBusinessSvc.GetSuggestions(searchForm.BusinessName, searchForm.StreetAddress, searchForm.City, searchForm.PostalCode);
                    AsyncManager.Parameters["suggestions"] = suggestions;
                }
                AsyncManager.Parameters["searchForm"] = searchForm;
                AsyncManager.OutstandingOperations.Decrement();
            }).Start();             
        }
    }

    public ActionResult SearchCompleted(BusinessSearchForm searchForm,IEnumerable<BusinessSuggestionBase> suggestions)
    {
        if (ModelState.IsValid)
        {
            TempData["suggestions"] = suggestions;
            return RedirectToAction("SearchResult");
        }
        return View(searchForm);
    }