scope - PHP:无法从包含的文件访问对象

Question

这个问题在这里已经有了答案:





Call to a member function on a non-object [duplicate]

(8 个回答)


8年前关闭。




使用这个函数我想创建一个 PHP 导航:

function loadPage($pagename) {
        if (!isset($pagename) || !file_exists($pagename . '.php')) {
            include FRONTPAGE . '.php';
        } else {
            include $pagename . '.php';
        }
    }

在我的索引中，我有以下内容:

require 'includes/classes/core.php';
$core = new SH_Core();

我可以从 $core 访问所有其他类，如 $core->database->newConnection();
我也应该能够在包含的文件中使用它。但我不能:

Notice: Undefined variable: core in C:\Users\Development\Development applications\localhost\htdocs\Shuze\frontpage.php on line 4

Notice: Trying to get property of non-object in C:\Users\Development\Development applications\localhost\htdocs\Shuze\frontpage.php on line 4

Fatal error: Call to a member function newConnection() on a non-object in C:\Users\Development\Development applications\localhost\htdocs\Shuze\frontpage.php on line 4

Answer 1

您需要让您的函数访问 $core:

function loadPage( $pageName ) {
    global $core;
    //rest of code
}

您也可以放在包含文件的顶部。或者，您可以使用 super 全局 $GLOBALS['core']。