r - 对称矩阵上的对称性测试失败

Question

我在内存中有一个对称矩阵(4x4)。不幸的是， sum( originalMatrix != t( originalMatrix ) ) = 6. 所以我输入了那个矩阵并将它读回内存。现在 sum( dputMatrix!= t( dputMatrix) ) = 0. 这怎么可能，我如何测试内存矩阵的对称性？

originalMatrix = ...
sum( originalMatrix != t( originalMatrix ) )  # results in 6
dput( originalMatrix )
dputMatrix = structure(c(0.00117771346463494, -1.57864028664711e-05, 0.000293652924987303, 
-9.85387333663002e-05, -1.57864028664711e-05, 0.000194782042576016, 
6.9133672862693e-05, 4.23792732612071e-05, 0.000293652924987303, 
6.9133672862693e-05, 0.00046216043028767, 2.70172523991749e-05, 
-9.85387333663002e-05, 4.23792732612071e-05, 2.70172523991749e-05, 
0.00017694896679169), .Dim = c(4L, 4L), .Dimnames = list(c("a00088630", 
"a0091n", "a01010", "a01307810"), c("a00088630", "a0091n", "a01010", 
"a01307810")))
sum( dputMatrix != t( dputMatrix ) )  # results in 0!!!

Answer 1

这是FAQ 7.31的体现。请注意，如果要将 R 对象保存到全精度，则应使用 save()。

请打勾!