Django for loop 模板(使用 for 循环打印有限的数据)

Question

假设我有 100电影。在 for 循环的帮助下。我们可以打印所有的电影。像下面。

在 Django 模板中

{% for movie in movies.object_list %}

    {% endfor %}

但是如果我只需要打印 1 我该怎么办 25 50 75 100列表中的电影？谢谢

更新:我写了这个。还有另一种选择吗？

{% for movie in movies.object_list %}
        {% if forloop.counter == 25 %}

            {{ movie }}

        {% endif %}

        {% if forloop.counter == 50 %}

            {{ movie }}

        {% endif %}
        {% if forloop.counter == 75 %}

            {{ movie }}

        {% endif %}
        {% if forloop.counter == 100 %}

            {{ movie }}

        {% endif %}
    {% endfor %}

View

def movie_sort(request):
categories = Category.objects.all()
language_name = Category.objects.get(id=request.GET.get('language'))
movie_l = Movie.objects.filter(language=request.GET.get('language'),is_active=True)
   # Displaying first row 
for i, v in enumerate(movie_l):
   if i == 0:
       first_row_f = v
   if i == 24:
       first_row_l = v
   if i == 25:
       second_row_f = v
   if i == 49:
       second_row_l = v
   if i == 50:
       third_row_f = v
   if i == 74:
       third_row_l = v
   if i == 75:
       fourth_row_f = v
   if i == 99:
       fourth_row_l = v
################
paginator = Paginator(movie_l, 100) # Show 25 contacts per page

page = request.GET.get('page',1)
try:
    movies = paginator.page(page)
except PageNotAnInteger:
    movies = paginator.page(1)
except EmptyPage:
    movies = paginator.page(paginator.num_pages)
return render_to_response('movie/alphabetic_list.html',locals(),
                          context_instance=RequestContext(request))

UPDATE2:我在 view 中编写了以下函数.如果用户单击下一页(分页器)，则唯一的问题是它会显示以前的数据。意味着这个数据不会改变。有什么建议吗？

  for i, v in enumerate(movie):
   if i == 0:
       first_row_f = v
   if i == 24:
       first_row_l = v
   if i == 25:
       second_row_f = v
   if i == 49:
       second_row_l = v
   if i == 50:
       third_row_f = v
   if i == 74:
       third_row_l = v
   if i == 75:
       fourth_row_f = v
   if i == 99:
       fourth_row_l = v

Answer 1

您必须包含 enumerate(movie.object_list)

    for i, v in enumerate(movie.object_list):
   if i == 0:
       first_row_f = v
   if i == 24:
       first_row_l = v
   if i == 25:
       second_row_f = v
   if i == 49:
       second_row_l = v
   if i == 50:
       third_row_f = v
   if i == 74:
       third_row_l = v
   if i == 75:
       fourth_row_f = v
   if i == 99:
       fourth_row_l = v