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ruby-on-rails - 有没有办法急切加载多态关联的关联?

转载 作者:行者123 更新时间:2023-12-04 05:51:04 32 4
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艺术家有很多事件(基本上是用户之间交互的缓存):

class Activity < ActiveRecord::Base

belongs_to :receiver, :class_name => 'Artist', :foreign_key => :receiver_id #owns the stuff done "TO" him
belongs_to :link, :polymorphic => true
belongs_to :creator, :class_name => 'Artist', :foreign_key => :creator_id #person who initiated the activity

end

例如:
  Activity.create(:receiver_id => author_id, :creator_id => artist_id, :link_id => id, :link_type => 'ArtRating') 

我想为每个艺术家创建一个事件流页面,由不同类型的事件列表、ArtRatings(喜欢、不喜欢)、收藏、关注等组成。

Controller 如下所示:
class ActivityStreamController < ApplicationController
def index
@activities = @artist.activities.includes([:link,:creator,:receiver]).order("id DESC").limit(30)
end
end

db 调用正确地急切地加载多态链接对象:
  SELECT "activities".* FROM "activities" WHERE (("activities"."receiver_id" = 6 OR "activities"."creator_id" = 6)) ORDER BY id DESC LIMIT 30
ArtRating Load (0.5ms) SELECT "art_ratings".* FROM "art_ratings" WHERE "art_ratings"."id" IN (137, 136, 133, 130, 126, 125, 114, 104, 103, 95, 85, 80, 73, 64)
SELECT "follows".* FROM "follows" WHERE "follows"."id" IN (14, 10)
SELECT "favorites".* FROM "favorites" WHERE "favorites"."id" IN (25, 16, 14)

但是当我显示每个ArtRating时,我还需要引用帖子标题,它属于一个帖子。在 View 中,如果我这样做:
activity.link.post

它对每个 art_rating 的帖子进行单独的数据库调用。有没有办法也可以急切地加载帖子?

问题更新:

如果无法使用“包含”语法实现帖子的预加载,有没有办法自己手动执行预加载查询并将其注入(inject)@activities 对象?

我在数据库日志中看到:
SELECT "art_ratings".* FROM "art_ratings" WHERE "art_ratings"."id" IN (137, 136, 133, 130, 126, 125, 114, 104, 103, 95, 85, 80, 73, 64)

有没有办法可以从 @activities 对象访问这个 id 列表?如果是这样,我可以做 2 个额外的查询,1 个来获取该列表中的 art_ratings.post_id(s),另一个来选择这些 post_ids 列表中的所有帖子。然后以某种方式将“发布”结果注入(inject)@activities,以便在我遍历集合时它可以作为 activity.link.post 使用。可能的?

最佳答案

TL;DR 我的解决方案使 artist.created_activities.includes(:link)急切地加载你想要的一切

这是我的第一次尝试:https://github.com/JohnAmican/music

几点注意事项:

  • 我依赖 default_scope ,所以这不是最优的。
  • 看起来您正在使用 STI。我的解决方案没有。这意味着您不能简单地调用activities关于艺术家;您必须引用 created_activitiesreceived_activities .可能有办法解决这个问题。如果我发现任何东西,我会更新。
  • 我改变了一些名字,因为否则它会让我感到困惑。

  • 如果您进入控制台并执行 created_activities.includes(:link) ,适当的东西被急切地加载:
    irb(main):018:0> artist.created_activities.includes(:link)
    Activity Load (0.2ms) SELECT "activities".* FROM "activities" WHERE "activities"."creator_id" = ? [["creator_id", 1]]
    Rating Load (0.3ms) SELECT "ratings".* FROM "ratings" WHERE "ratings"."id" IN (1)
    RatingExplanation Load (0.3ms) SELECT "rating_explanations".* FROM "rating_explanations" WHERE "rating_explanations"."rating_id" IN (1)
    Following Load (0.3ms) SELECT "followings".* FROM "followings" WHERE "followings"."id" IN (1)
    Favorite Load (0.2ms) SELECT "favorites".* FROM "favorites" WHERE "favorites"."id" IN (1)
    => #<ActiveRecord::Relation [#<Activity id: 1, receiver_id: 2, creator_id: 1, link_id: 1, link_type: "Rating", created_at: "2013-10-31 02:36:27", updated_at: "2013-10-31 02:36:27">, #<Activity id: 2, receiver_id: 2, creator_id: 1, link_id: 1, link_type: "Following", created_at: "2013-10-31 02:36:41", updated_at: "2013-10-31 02:36:41">, #<Activity id: 3, receiver_id: 2, creator_id: 1, link_id: 1, link_type: "Favorite", created_at: "2013-10-31 02:37:04", updated_at: "2013-10-31 02:37:04">]>

    至少,这证明了 Rails 有能力做到这一点。规避 default_scope告诉 Rails 你想做什么似乎是一个问题,而不是技术限制。

    更新:

    事实证明,当您将范围 block 传递给关联并调用该关联时, self在该 block 内指的是关系。因此,您可以反射(reflection)并采取适当的行动:
    class Activity < ActiveRecord::Base
    belongs_to :creator, class_name: 'Artist', foreign_key: :creator_id, inverse_of: :created_activities
    belongs_to :receiver, class_name: 'Artist', foreign_key: :receiver_id, inverse_of: :received_activities
    belongs_to :link, -> { self.reflections[:activity].active_record == Rating ? includes(:rating_explanation) : scoped }, polymorphic: true
    end

    我更新了我的代码以反射(reflect)(哈哈)这一点。

    这可以清理。例如,也许您并不总是想要预先加载 rating_explanations访问事件链接时。有很多方法可以解决这个问题。如果你愿意,我可以发一个。

    但是,我认为这表明最重要的是 在关联的范围 block 内,您可以访问 ActiveRecord::Relation正在 build 。这将允许您有条件地对其进行操作。

    关于ruby-on-rails - 有没有办法急切加载多态关联的关联?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8652085/

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