php - Yammer - 如何通过 api 发布到事件流？ (PHP)

Question

我能够“获取”事件流，但不能“发布”到它。看来是技术错误。
这是用于获取事件流的代码:

function getActivityStream()
{
    $as=$this->request('https://www.yammer.com/api/v1/streams/activities.json');
    var_dump($as);
}

function request($url, $data = array())
{
    if (empty($this->oatoken)) $this->getAccessToken();
    $headers = array();
    $headers[] = "Authorization: Bearer " . $this->oatoken['token'];
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $url . '?' . http_build_query($data) );
    curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    $output = curl_exec($ch);
    return json_decode($output);
}

好的，这样工作正常......
下面的代码，返回一个 Yammer “哎呀，找不到这个页面”信息:

function putActivityStream()
{
    $data=array('type'=>'text', 'text'=>'hello from api test call');
    $json=json_encode($data);
    $res=$this->post('streams/activites.json',$json);
}

function post($resource, $data)
{
    if (empty($this->oatoken)) $this->getAccessToken();
    $ch = curl_init();
    $headers = array();
    $headers[] = "Authorization: Bearer " . $this->oatoken['token'];
    $headers[]='Content-Type: application/json';
    $url = 'https://www.yammer.com/api/v1/' . $resource;
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_POST, true);
    curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
    $response = curl_exec($ch);
    return $response;
}

示例之一来自:
http://developer.yammer.com/api/streams.html

POST https://www.yammer.com/api/v1/streams/activities.json
Requests must be content-type: application/json.

{
  "type": "text",
  "text": "The build is broken."
}

Answer 1

你会踢自己。你的代码有错别字。 :)
改变:

$res=$this->post('streams/activites.json',$json);

到

$res=$this->post('streams/activities.json',$json);

简单。