symfony - 在 where 条件下的学说 ORM 计数数组集合

Question

使用 Symfony2.8与 Doctrine 2.5 ，我想在 Doctrine ORM 查询中过滤 arraycollection 正好包含 3 个元素的所有数据集。

$em = $this->getDoctrine()->getManager();
$query = $em->getRepository("AppBundle:EduStructItem")
->createQueryBuilder('e')
 ->addSelect('COUNT(e.preconditions) AS HIDDEN numberpre')
 ->having('numberpre = 3')
->getQuery();
$res = $query->getResult();
dump($res);
foreach ($res as $entity){
    print "title:".$entity->getTitle()."<br>";
    dump($entity->getPreconditions()->toArray());
}

preconditions是一个包含先决条件集合的数组集合。

最后，我想获得恰好具有 3 个先决条件的所有结果。
此外，按 arraycollection 中的值数量排序也很棒(类似于 order by Count(e.preconditions) )。

由于使用了另一个包，我将学说从 2.5.2 降级到 2.5.0。我不认为这是我的问题的原因，但为了完整起见，这里是我的 Composer 表演的教义部分:

data-dog/pager-bundle                v0.2.4             Paginator bundle for symfony2 and doctrine orm, allows customization with filters and sorters
  doctrine/annotations                 v1.2.7             Docblock Annotations Parser
  doctrine/cache                       v1.5.2             Caching library offering an object-oriented API for many cache backends
  doctrine/collections                 v1.3.0             Collections Abstraction library
  doctrine/common                      v2.5.2             Common Library for Doctrine projects
  doctrine/data-fixtures               v1.1.1             Data Fixtures for all Doctrine Object Managers
  doctrine/dbal                        v2.5.2             Database Abstraction Layer
  doctrine/doctrine-bundle             1.6.1              Symfony DoctrineBundle
  doctrine/doctrine-cache-bundle       1.2.2              Symfony Bundle for Doctrine Cache
  doctrine/doctrine-fixtures-bundle    2.3.0              Symfony DoctrineFixturesBundle
  doctrine/doctrine-migrations-bundle  1.1.1              Symfony DoctrineMigrationsBundle
  doctrine/inflector                   v1.1.0             Common String Manipulations with regard to casing and singular/plural rules.
  doctrine/instantiator                1.0.5              A small, lightweight utility to instantiate objects in PHP without invoking their constructors
  doctrine/lexer                       v1.0.1             Base library for a lexer that can be used in Top-Down, Recursive Descent Parsers.
  doctrine/migrations                  v1.1.0             Database Schema migrations using Doctrine DBAL
  doctrine/orm                         v2.5.0             Object-Relational-Mapper for PHP             

这是一个测试实体:

<?php
// src/AppBundle/Entity/EduStructItem.php
namespace AppBundle\Entity;


use Doctrine\Common\Collections\ArrayCollection;
use Doctrine\ORM\Mapping as ORM;
use Symfony\Component\Validator\Constraints as Assert;

/**
 * @ORM\Entity
 * @ORM\Table(name="test_edustructitemcollection")
 */
class EduStructItem
{
    /**
     * @ORM\Column(type="integer")
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    protected $id;


    /**
     * @var string
     * @Assert\NotBlank()
     * @ORM\Column(type="string", length=255, nullable=false)
     */
    private $title;


    /**
     * Preconditions are EduStructItems referencing to an EduStructItem.
     * For a single EduStructItem its empty (which have no subelements).
     * A join table holds the references of a main EduStructItem to its sub-EduStructItems (preconditions)
     *
     * @ORM\ManyToMany(targetEntity="EduStructItem",indexBy="id", cascade={"persist"})
     * @ORM\JoinTable(name="test_edustructitem_preconditioncollection",
     *     joinColumns={@ORM\JoinColumn(name="edustructitem_id", referencedColumnName="id")},
     *     inverseJoinColumns={@ORM\JoinColumn(name="edustructitem_precondition_id", referencedColumnName="id")}
     * )
     */
    public $preconditions;

    public function __construct()
    {
        $this->preconditions = new ArrayCollection();
    }

    public function getTitle()
    {
        return $this->title;
    }

    public function setTitle($title)
    {
        $this->title = $title;
    }


    public function getPreconditions()
    {
        return $this->preconditions;
    }

    public function addPrecondition(\AppBundle\Entity\EduStructItem $precondition)
    {
        $this->preconditions->add($precondition);
    }

    public function removePrecondition(\AppBundle\Entity\EduStructItem $precondition)
    {
        $this->preconditions->removeElement($precondition);
    }

}
?>

最后我总是得到错误:
[语义错误] 'preconditions)' 附近的第 0 行第 18 列:错误:无效的 PathExpression。预期的 StateFieldPathExpression 或 SingleValuedAssociationField。

现在我尝试了你的新解决方案:

$em = $this->getDoctrine()->getManager();
$query = $em->getRepository("AppBundle:EduStructItem")
    ->createQueryBuilder('e')
    ->addSelect('COUNT(e.preconditions) AS HIDDEN countpre')
    ->join('e.preconditions', 'precondition', Join::WITH)
    ->having('countpre = 1')
    ->getQuery();

并再次得到错误:
[语义错误] 'preconditions)' 附近的第 0 行第 18 列:错误:无效的 PathExpression。预期的 StateFieldPathExpression 或 SingleValuedAssociationField。 Wenn 我在 HIDDEN 之前写了别名，我也得到了:[语义错误] line 0, col 53 near 'FROM AppBundle\Entity\EduStructItem': Error: Class 'FROM' is not defined。考虑到它是一种自反射(reflect)关系，只有一个实体但有两个表。正如您在我的实体的注释中所看到的，自我关系保存在 test_edustructitem_preconditioncollection - 表中，该表由于注释而由学说生成。

我尝试了您的最新解决方案:

$qb = $em->getRepository("AppBundle:EduStructItem")
    ->createQueryBuilder('item');
$qb->addSelect('COUNT(precondition.id) AS countpre HIDDEN ')
    ->join('item.preconditions', 'precondition', Join::WITH)
    ->having('countpre = 1');

当我在 HIDDEN 之前使用 countpre 时，我总是收到此错误:
[语义错误] 'FROM AppBundle\Entity\EduStructItem' 附近的第 0 行第 56 列:错误:未定义类 'FROM'。

但是当我把 countpre 放在 HIDDEN 之后:

$qb = $em->getRepository("AppBundle:EduStructItem")
            ->createQueryBuilder('item');
        $qb->addSelect('COUNT(precondition.id) AS HIDDEN countpre')
            ->join('item.preconditions', 'precondition', Join::WITH)
            ->having('countpre = 1');

我收到错误:
执行 'SELECT t0_.id AS id_0, t0_.title AS title_1, COUNT(t1_.id) AS sclr_2 FROM test_edustructitemcollection t0_INNER JOIN test_edustructitem_preconditioncollection t2_ON t0_.id = t2_.edustructitemIN_1_0_.edustructitem_1. = t2_.edustructitem_precondition_id HAVING sclr_2 = 1':

SQLSTATE [42S22, 207]: [Microsoft][ODBC Driver 11 for SQL Server][SQL Server]Ungültiger Spaltenname 'sclr_2'。

500 内部服务器错误 - DBALException

1 个链接异常:SQLSrvException »

请考虑只有一个具有自引用的实体，并且有以下两个表:

USE [easylearndev4_rsc]
GO
/****** Object:  Table [dbo].[test_edustructitemcollection]    Script Date: 14.12.2015 09:31:55 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE TABLE [dbo].[test_edustructitemcollection](
    [id] [int] IDENTITY(1,1) NOT NULL,
    [title] [nvarchar](255) NOT NULL,
PRIMARY KEY CLUSTERED 
(
    [id] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO

和

USE [easylearndev4_rsc]
GO
/****** Object:  Table [dbo].[test_edustructitem_preconditioncollection]    Script Date: 14.12.2015 09:32:21 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
REATE TABLE [dbo].[test_edustructitem_preconditioncollection](
    [edustructitem_id] [int] NOT NULL,
    [edustructitem_precondition_id] [int] NOT NULL,
PRIMARY KEY CLUSTERED 
(
    [edustructitem_id] ASC,
    [edustructitem_precondition_id] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO
ALTER TABLE [dbo].[test_edustructitem_preconditioncollection]  WITH CHECK ADD  CONSTRAINT [FK_34E716A81B7A6CEB] FOREIGN KEY([edustructitem_precondition_id])
REFERENCES [dbo].[test_edustructitemcollection] ([id])
GO
ALTER TABLE [dbo].[test_edustructitem_preconditioncollection] CHECK CONSTRAINT [FK_34E716A81B7A6CEB]
GO
ALTER TABLE [dbo].[test_edustructitem_preconditioncollection]  WITH CHECK ADD  CONSTRAINT [FK_34E716A85D864668] FOREIGN KEY([edustructitem_id])
REFERENCES [dbo].[test_edustructitemcollection] ([id])
GO
ALTER TABLE [dbo].[test_edustructitem_preconditioncollection] CHECK CONSTRAINT [FK_34E716A85D864668]
GO

最后我自己找到了一个解决方法:

$em = $this->getDoctrine()->getManager();
$qb = $em->getRepository("AppBundle:EduStructItem")
    ->createQueryBuilder('e');
$qb->join('e.preconditions', 'p', Join::WITH)
    ->groupBy('e.id, e.title')
    ->having('count(p.id) = 1');

但是我对此不太满意，因为 arraycollection 已经是聚合数据，为什么我还要加入、计数和分组!
这不可能是教义的想法!
有谁知道更好的解决方案？

Answer 1

尝试这个:

$qb = $this->getDoctrine()->getManager()->getRepository("MyBundle:Groups")
    ->createQueryBuilder('g')
    ->having('count(g.members) = 3')
    ->orderBy('g.members', 'DESC')
;