localization - gawk float 本地化

Question

我希望 gawk 使用逗号 , 作为小数点字符来解析数字。所以我将 LC_NUMERIC 设置为 fr_FR.utf-8 但它不起作用:

echo 123,2 | LC_NUMERIC=fr_FR.utf-8 gawk '{printf ("%.2f\n", $1 + 0) }'
123.00

解决方案是指定选项 --posix 或 export POSIXLY_CORRECT=1 但在这种情况下 GNU awk 扩展不可用，例如 delete 或 gensub 函数:

echo 123,2 | LC_NUMERIC=fr_FR.utf-8 gawk --posix '{printf ("%.2f\n", $1 + 0) }'
123,20

是否可以在不指定的情况下将,作为小数点的gawk解析数POSIX 选项？

Answer 1

您正在寻找的选项是:

--use-lc-numeric

This forces gawk to use the locale's decimal point character when parsing input data. Although the POSIX standard requires thisbehavior, and gawk does so when --posix is in effect, the default isto follow traditional behavior and use a period as the decimalpoint, even in locales where the period is not the decimal pointcharacter. This option overrides the default behavior, without thefull draconian strictness of the --posix option.

演示:

$ echo 123,2 | LC_NUMERIC=fr_FR.utf-8 awk --use-lc-numeric '{printf "%.2f\n",$1}'
123,20

注意:printf 是语句而不是函数，因此不需要括号，我不确定为什么要在此处添加零？