php - 在 symfony 中插入带有 Doctrine 的\double 值

Question

我有一个叫做柏拉图的类，它扩展了 Producto 女巫包含的属性。 setter 在这里定义:

public function setPrecio(\double $precio)
{
   $this->precio = $precio;

   return $this;
}

我尝试向数据库添加一个新元素:

$plato = new Plato; 
$em = $this->getEntityManager();
 // I have tryed this three ways to insert
$plato->SetPrecio(doubleval($precio));  
$plato->SetPrecio((double) 2);
$plato->SetPrecio(2.0);

$em->flush();

它给了我以下错误消息:

Catchable Fatal Error: Argument 1 passed to Servinow\EntitiesBundle\Entity\Producto::setPrecio() must be an instance of double, double given, called in /Users/luis/git/servinowServer-luis/src/Servinow/EntitiesBundle/Entity/PlatoRepository.php on line 41 and defined in /Users/luis/git/servinowServer-luis/src/Servinow/EntitiesBundle/Entity/Producto.php line 169

Answer 1

修改 setPrecio()以这种方式发挥作用

public function setPrecio($precio)
{
   $this->precio = $precio;

   return $this;
}

你可以使用类似的东西

gettype($precio)[...];
if(is_numeric($precio))[...];

对于类型控制，在将其设置为 $this 之前

请记住

Type Hints can only be of the object and array (since PHP 5.1) type. Traditional type hinting with int and string isn't supported.