c - 为什么我的程序在没有收到任何新输入的情况下循环？

Question

我试图让我的程序在给出答案后重新开始。一旦我运行一次，它就不会再次运行。我想让它在用户不必再次启动程序的地方发挥作用。谢谢!

#include <stdio.h>
#include <math.h>


int main()
{
    float firstnum, secondnum, answer;
    char function;

    printf("\nHello and welcome to my calculator!\n");                                             //Intro

    start:                                                                                         //Area to loop to when program completes

    printf("\nPlease input the function you would like to use.  These include +, -, *, /.\n");     //Asking for function input

    scanf("%c", &function);                                                                        //Receiving Function Input

    printf("\nNow please input the two variables.\n");                                             //Asking for variables

    scanf("%f", &firstnum);

    scanf("%f", &secondnum);                                                                       //Receiving Input for Variables

    if (function == '+')                                                                           //Doing calculation
    {
            answer = firstnum+secondnum;
    }
    else if (function == '-')
    {
    answer = firstnum-secondnum;
    }
    else if (function == '*')
    {
    answer = firstnum*secondnum;
    }
    else if (function == '/')
    {
    answer = firstnum/secondnum;
    }
    else
    {
            printf("Sorry that was an incorrect function.  The correct inputs are +, -, *, /.");       //If they don't follow the directions
    }

    printf("Your answer is %f \n", answer);                                                        //Answer

    goto start;                                                                                    //Loop

return 0;

}

Answer 1

这就是您使用循环的原因。 (并尽量不要为此使用 goto)。

#include <stdio.h>
#include <math.h>


int main() {

    float firstnum, secondnum, answer;
    char function, buffer[2];

    while(1) {      

        printf("\nHello and welcome to my calculator!\n");                                             

        printf("\nPlease input the function you would like to use.  These include +, -, *, /.\n");     
        scanf("%s", &buffer);   
        function = buffer[0];
        printf("\nNow please input the two variables.\n");  
        scanf("%f", &firstnum);
        scanf("%f", &secondnum);
        if (function == '+') answer = firstnum+secondnum;
        else if (function == '-') answer = firstnum-secondnum;
        else if (function == '*') answer = firstnum*secondnum;
        else if (function == '/') answer = firstnum/secondnum;
        else printf("Sorry that was an incorrect function.  The correct inputs are +, -, *, /.");    

        printf("Your answer is %f \n", answer);                                                               
        } 

     return 0;
     }

这应该是一个无限循环，所以使用用户输入到 break;退出程序的循环

注意:我已将 scanf %c 替换为 %s 以指示字符串的输入并使用了缓冲区。

 scanf("%s",&buffer); function = buffer[0];

(根据评论中的讨论更新)