oracle - 如何将选择结果存储到Oracle过程中的变量中

Question

我写了一个简单的程序。我尝试将选择结果存储在变量中。我使用“SELECT INTO”查询，但无法执行此操作。

例子:

DECLARE
     v_employeeRecord  employee%ROWTYPE;
BEGIN
 SELECT * INTO v_employeeRecord
      FROM Employee WHERE Salary > 10;
END;

Answer 1

您有几种选择。您可以将该查询转换为游标:

DECLARE
     CURSOR v_employeeRecords IS
          SELECT * FROM Employee WHERE Salary > 10;
     v_employeeRecord  employee%ROWTYPE;
BEGIN
     FOR v_employeeRecord IN v_employeeRecords LOOP
          /* Do something with v_employeeRecord */
     END LOOP;
END;

或者，您可以创建一个 TABLE变量:

DECLARE
     v_employeeRecord  employee%ROWTYPE;
     v_employeeRecords IS TABLE OF employee%ROWTYPE;
     i BINARY_INTEGER;
BEGIN
 SELECT * BULK COLLECT INTO v_employeeRecords
      FROM Employee WHERE Salary > 10;

 i := v_employeeRecords.FIRST;
 WHILE v_employeeRecords.EXISTS(i) LOOP
     v_employeeRecord := v_employeeRecords(i);
     /* Do something with v_employeeRecord */
     i := v_employeeRecords.NEXT(i);
 END;
END;

我没有在Oracle中尝试过这些示例，因此您可能会遇到编译器错误...