php - fatal error : Cannot redeclare getteampoints() (previously declared in

Question

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8年前关闭。




得到了以下函数，之前没有在任何地方声明 getteampoints 值。试图遵循其他重新声明错误问题，但没有一个奏效。我该如何解决这个问题？

function getTeamPoints($team)
    {
        $query = mysql_query("SELECT * FROM Team_comp WHERE t_id='$team'");
        $team_array = array();

        while($a = mysql_fetch_array($query))
        {
            $team_array = array(            'home_won'  =>  $a['home_win'],
                                            'home_draw' =>  $a['home_tie'],
                                            'home_lost' =>  $a['home_lost'],
                                            'away_won'  =>  $a['away_win'],
                                            'away_draw' =>  $a['away_tie'],
                                            'away_lost' =>  $a['away_lost'],
                                            'home_games'=>  $a['home_games'],
                                            'away_games'=>  $a['away_games']);
        }

        return $team_array;
    }

    function calculateTeamPoints($team, $type)
    {
        $teamPts = getTeamPoints($team);

        if($type == 'home')
        {
            $homem = $teamPts['home_games'];
            $homew = $teamPts['home_won'];
            $percent = ($homew * 100) / $homem;

            $remaining = $homem - $homew;

            $per = ($remaining * 100) / $homem;
            $percent += $per / 2;
        }
        elseif($type == 'away')
        {
            $homem = $teamPts['away_games'];
            $homew = $teamPts['away_won'];
            $percent = ($homew * 100) / $homem;

            $remaining = $homem - $homew ;

            $per = ($remaining * 100) / $homem;
            $percent += $per / 2;
        }

        return $percent;
    }

    function getpercent($hometeamid, $awayteamid)
    {
        $hometeampts = calculateTeamPoints($hometeamid, 'home');
        $awayteampts = calculateTeamPoints($awayteamid, 'away');


        $homepercent = floor(($hometeampts - $awayteampts) + 50);
        $awaypercent = 100-$homepercent;


    }

    //demo
    getpercent($hometeamid, $awayteamid);
    ?>

Answer 1

将如何函数 getTeamPoints 放入 IF 条件中..

if(!function_exists('getTeamPoints')){ 
    function getTeamPoints()....

}

不可能不止一次声明 1 个函数!

如果您声明它超过 1 次，您必须编写不同的名称，如果您只包含该文件超过 1 次(这是错误的..)，此 IF 函数存在检查将正常工作。