ecmascript-6 - 在构造函数中获取类名

Question

export class InvalidCredentialsError extends Error {
  constructor(msg) {
    super(msg);
    this.message = msg;
    this.name = 'InvalidCredentialsError';
  }
}

正如你在上面看到的，我正在写 InvalidCredentialsError两次。有没有办法以某种方式获取构造函数方法中已有的类名并设置它？还是对象必须被实例化？

Answer 1

在具有原生 ES6 类支持的浏览器中，this.constructor.name将显示 InvalidCredentialsError .如果你用 Babel 编译代码，它会显示 错误 .

没有 Babel(在 Chrome 或其他支持类的浏览器上使用):

class InvalidCredentialsError extends Error {
  constructor(msg) {
    super(msg);
    console.log(this.constructor.name);
    this.message = msg;
    this.name = 'InvalidCredentialsError';
  }
}

const instance = new InvalidCredentialsError('message');

与巴别塔:

class InvalidCredentialsError extends Error {
  constructor(msg) {
    super(msg);
    console.log(this.constructor.name);
    this.message = msg;
    this.name = 'InvalidCredentialsError';
  }
}

const instance = new InvalidCredentialsError('message');