甲骨文。如何输出日期和时间？

Question

我的访问表如下:

insert into Visit
values(12, to_date('19-JUN-13', 'dd-mon-yy'), to_date('19-JUN-13 12:00 A.M.' , 'dd-mon-yy hh:mi A.M.'));
insert into Visit
values(15, to_date('20-JUN-13', 'dd-mon-yy'), to_date('20-JUN-13 02:00 A.M.' , 'dd-mon-yy hh:mi A.M.'));
insert into Visit
values(18, to_date('21-JUN-13', 'dd-mon-yy'), to_date('21-JUN-13 10:30 A.M.' , 'dd-mon-yy hh:mi A.M.'));

当我尝试查询它时: select * from Visit我得到:

SQL> select * from visit;

   SLOTNUM DATEVISIT ACTUALARRIVALTIME                                                                                                                                                                                                                                                                                                                                                                                 
---------- --------- ------------------------------                                                                                                                                                                                                                                                                                                                                                                     
        12 19-JUN-13 19-JUN-13                                                                                                                                                                                                                                                                                                                                                                                                                                                                                       
        15 20-JUN-13 20-JUN-13                                                                                                                                                                                                       
        18 21-JUN-13 21-JUN-13                                                                                                                                                                                                      

SQL> spool off;

怎么没时间？

Answer 1

您还可以设置适用于所有日期的格式，如下所示:

ALTER SESSION SET NLS_DATE_FORMAT = 'DD-MON-YYYY HH:MI:SS PM';

这样，您的原始查询将以您所追求的格式输出日期，而无需使用 TO_CHAR .要设置回通常的默认格式，只需执行以下操作:

ALTER SESSION SET NLS_DATE_FORMAT = 'DD-MON-RR';