spring-batch - 条件为假时如何跳过批处理步骤

Question

我有一项基本工作，只有一个基本步骤。该作业每 x 秒执行一次(我为此使用了 quartz )。然后在我的配置类中我也有变量“runStep”。仅当 runStep 为 true 时，我应该在哪里添加此属性并运行我的步骤？

<batch:job id="export1" parent="baseJob">
    <batch:step id="registruj" parent="baseStep">
        <tasklet>
            <chunk reader="registrujReader" processor="registrujProcessor" writer="registrujWriter"
                commit-interval="1" />
        </tasklet>
    </batch:step>
</batch:job>

<bean id="baseJob" class="org.springframework.batch.core.job.SimpleJob" abstract="true">
    <property name="jobRepository" ref="jobRepository" />
</bean>

<bean id="baseStep" class="org.springframework.batch.core.step.factory.SimpleStepFactoryBean" abstract="true">
    <property name="transactionManager" ref="transactionManager" />
    <property name="jobRepository" ref="jobRepository" />
    <property name="startLimit" value="100" />
    <property name="commitInterval" value="1" />
</bean>

<bean id="jobRepository" class="org.springframework.batch.core.repository.support.JobRepositoryFactoryBean"
    p:dataSource-ref="expDataSource" p:transactionManager-ref="transactionManager" />

<bean id="jobLauncher" class="org.springframework.batch.core.launch.support.SimpleJobLauncher">
    <property name="jobRepository" ref="jobRepository" />
</bean>

<bean class="org.springframework.batch.core.configuration.support.JobRegistryBeanPostProcessor">
    <property name="jobRegistry" ref="jobRegistry" />
</bean>

<bean id="jobRegistry" class="org.springframework.batch.core.configuration.support.MapJobRegistry" />

<bean id="registrujWriter" class="cz.isvs.reg.rob.util.export.batch.RegistrujItemWriter" scope="step" />
<bean id="registrujReader" class="cz.isvs.reg.rob.util.export.batch.RegistrujItemReader" scope="step" />
<bean id="registrujProcessor" class="cz.isvs.reg.rob.util.export.batch.RegistrujItemProcessor" scope="step" />

<!-- run every 10 seconds -->
<bean class="org.springframework.scheduling.quartz.SchedulerFactoryBean">
    <property name="triggers">
        <bean id="cronTrigger" class="org.springframework.scheduling.quartz.CronTriggerBean">
            <property name="jobDetail" ref="jobDetail" />
            <property name="cronExpression" value="*/10 * * * * ?" />
        </bean>
    </property>
</bean>

<bean id="jobDetail" class="org.springframework.scheduling.quartz.JobDetailBean">
    <property name="jobClass" value="cz.isvs.reg.rob.util.export.batch.JobLauncherDetails" />
    <property name="group" value="quartz-batch" />
    <property name="jobDataAsMap">
        <map>
            <entry key="jobName" value="export1" />
            <entry key="jobLocator" value-ref="jobRegistry" />
            <entry key="jobLauncher" value-ref="jobLauncher" />
        </map>
    </property>
</bean>

Answer 1

使用 JobExecutionDecider

public class RunStepDecider implements JobExecutionDecider {
  public FlowExecutionStatus decide(JobExecution jobExecution, StepExecution stepExecution) {
    final String runStep = jobExecution.getJobParameters().getString("runStep");
    //Depending on the above condition you can return Completed or Failed.
    return new FlowExecutionStatus.COMPLETED;
  }
}

<batch:job id="export1" parent="baseJob">
  <decision id="decision" decider="decider">
    <next on="COMPLETED" to="registruj" />
  </decision>
  <batch:step id="registruj" parent="baseStep">
    <tasklet>
      <chunk reader="registrujReader" processor="registrujProcessor" writer="registrujWriter" commit-interval="1" />
    </tasklet>
  </batch:step>
</batch:job>


<bean id="decider" class="RunStepDecider" />

并将 runStep 作为 JobParameter 传递。

希望能帮助您解决问题。