xcode - 直接访问 Objective-C 的 isa 已弃用，取而代之的是 object_getClass()

Question

这是我要更改的代码:

       if(JK_EXPECT_T(object->isa == encodeState->fastClassLookup.stringClass))     { isClass = JKClassString;     }
  else if(JK_EXPECT_T(object->isa == encodeState->fastClassLookup.numberClass))     { isClass = JKClassNumber;     }
  else if(JK_EXPECT_T(object->isa == encodeState->fastClassLookup.dictionaryClass)) { isClass = JKClassDictionary; }
  else if(JK_EXPECT_T(object->isa == encodeState->fastClassLookup.arrayClass))      { isClass = JKClassArray;      }
  else if(JK_EXPECT_T(object->isa == encodeState->fastClassLookup.nullClass))       { isClass = JKClassNull;       }
  else {
  slowClassLookup:
         if(JK_EXPECT_T([object isKindOfClass:[NSString     class]])) { if(workAroundMacOSXABIBreakingBug == NO) { encodeState->fastClassLookup.stringClass     = object->isa; } isClass = JKClassString;     }
    else if(JK_EXPECT_T([object isKindOfClass:[NSNumber     class]])) { if(workAroundMacOSXABIBreakingBug == NO) { encodeState->fastClassLookup.numberClass     = object->isa; } isClass = JKClassNumber;     }
    else if(JK_EXPECT_T([object isKindOfClass:[NSDictionary class]])) { if(workAroundMacOSXABIBreakingBug == NO) { encodeState->fastClassLookup.dictionaryClass = object->isa; } isClass = JKClassDictionary; }
    else if(JK_EXPECT_T([object isKindOfClass:[NSArray      class]])) { if(workAroundMacOSXABIBreakingBug == NO) { encodeState->fastClassLookup.arrayClass      = object->isa; } isClass = JKClassArray;      }
    else if(JK_EXPECT_T([object isKindOfClass:[NSNull       class]])) { if(workAroundMacOSXABIBreakingBug == NO) { encodeState->fastClassLookup.nullClass       = object->isa; } isClass = JKClassNull;       }
            if(JK_EXPECT_F((keyObject->isa      != encodeState->fastClassLookup.stringClass)) && JK_EXPECT_F(([keyObject   isKindOfClass:[NSString class]] == NO))) { jk_encode_error(encodeState, @"Key must be a string object."); return(1); }

我应该如何改变它？

Answer 1

替换

object->isa

与

object_getClass(object)