c - 使用双指针访问链表的节点

Question

我正在尝试在链表中添加节点，传递指针指针，访问成员 (*list) -> next 给出了段错误。有人可以指出错误，提前致谢。代码是

void initializeList (node ** head, int data)
{
    *head = malloc (sizeof (node));
    (*head)-> member = data;
    (*head)-> next = NULL;
}

void addNode(node ** list, int data)
{
    node * newNode = NULL;
    newNode = malloc (sizeof (node));
    while (*list->next!= NULL) 
    {
        *list= (*list) -> next;
    }
    newNode -> member = data;
    newNode -> next = NULL;
    (*list) -> next = newNode;
}

void main ()
{
    node * head = NULL;
    initializeList (&head, 5);
    addNode(&head, 6);
}

Answer 1

您不应该取消对 NULL 指针的引用，否则会按预期获得 Seg Fault。

这是问题所在:

while (*list != NULL)
    {
    *list= (*list) -> next;
    }
newNode -> member = data;
newNode -> next = NULL;
(*list) -> next = newNode;

*list while 循环后为 NULL。
而你正在做 (*list) -> next = newNode;