gpt4 book ai didi

mocking - 使用 axios 拦截器模拟 axios

转载 作者:行者123 更新时间:2023-12-04 04:36:28 26 4
gpt4 key购买 nike

我正在尝试使用 mockAxios 来测试 axios 拦截器。

export default {
get: jest.fn(() => Promise.resolve({ data: {} }))
}

import axios from 'axios';

export const configurateAxios = () => {
axios.interceptors.response.use(
response => {
return response;
},
error => {
return Promise.reject(error);
}
);
}
当我创建 mockAxios 时:
export default {
get: jest.fn(() => Promise.resolve(data: {}))
}
我的所有测试都失败并显示以下消息:无法读取 axios 拦截器内部未定义的属性响应。这是因为模拟 axios 不返回响应。它可以只返回一个普通对象。
那么如何使用带有 mockAxios 的 axios 拦截器进行测试呢?

最佳答案

这是我如何实现的
拦截器.js

/* Module that I want to test
* Intercepts every axios request and redirects to login on 401
*/

import axios from 'axios';

export default () => {
axios.interceptors.response.use(
response => {
// Return a successful response back to the calling service
return response;
},
error => {
// Return any error which is not due to authentication back to the calling service
if (error.response.status !== 401) {
return new Promise((resolve, reject) => {
reject(error);
});
} else {
window.location.href = '/operator-portal/login';
return false;
}
}
);
};
拦截器.test.js
import axios from 'axios';
import interceptor from '../../src/apis/interceptor';

jest.mock('axios');

describe('interceptor', () => {
it('redirects to login route when response status is 401', () => {
delete global.window.location;
global.window = Object.create(window);
Object.defineProperty(window, 'location', {
value: {
href: 'url'
}
});
axios.interceptors.response.use = jest.fn((successCb, failCb) => {
failCb({
response: {
status: 401
}
});
});
interceptor();
expect(window.location.href).toEqual('/login');
});

it('redirects to login route when success handler is called', () => {
axios.interceptors.response.use = jest.fn(successCb => {
successCb();
});
interceptor();
window.location.href = 'url';
expect(window.location.href).toEqual('url');
});
});

关于mocking - 使用 axios 拦截器模拟 axios,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54483256/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com