firebase - 如何处理 Firebase Storage StorageException

Question

我的应用从 Firebase 存储中获取图像。如果不存在图像，我希望能够处理错误。但我似乎无法让它工作。

我试过用 try catch 包围。

我试过这个

Future<dynamic> getImage(int index){
      return FirebaseStorage.instance.ref().child(widget.snap[index].data['英文品名']+".jpg").getDownloadURL().catchError((onError){
        print(onError);
      }); 
 }

和这个

 Future<dynamic> getImage(int index){
   var imageStream;
   try {
       imageStream = FirebaseStorage.instance.ref().child(widget.snap[index].data['英文品名']+".jpg").getDownloadURL();    
   } catch (e) {
     print(e);
   }
   return imageStream;
 }

但我总是收到未处理的异常错误并且我的应用程序崩溃。

E/StorageException(11819): StorageException has occurred.
E/StorageException(11819): Object does not exist at location.
E/StorageException(11819):  Code: -13010 HttpResult: 404
E/StorageException(11819): StorageException has occurred.
E/StorageException(11819): Object does not exist at location.
E/StorageException(11819):  Code: -13010 HttpResult: 404
E/StorageException(11819): {  "error": {    "code": 404,    "message": "Not Found.  Could not get object",    "status": "GET_OBJECT"  }}
E/StorageException(11819): java.io.IOException: {  "error": {    "code": 404,    "message": "Not Found.  Could not get object",    "status": "GET_OBJECT"  }}

如何处理这个异常？
Image of exception in VS Code

Answer 1

根据图像的大小，上传文件将花费不同的时间。所以很可能你的错误是因为 async 和 await 的错误组合。这段代码对我有用。

Future<String> uploadSingleImage(File file) async {
    //Set File Name
    String fileName = DateTime.now().millisecondsSinceEpoch.toString() +
        AuthRepository.getUser().uid +
        '.jpg';
    
    //Create Reference
    Reference reference = FirebaseStorage.instance
        .ref()
        .child('Single Post Images')
        .child(fileName);

    //Now We have to check status of UploadTask
    UploadTask uploadTask = reference.putFile(file);
    
    String url;
    await uploadTask.whenComplete(() async {
      url = await uploadTask.snapshot.ref.getDownloadURL();
    });
    print('before return');
    return url;
  }