sql - 选择不同的返回重复项

Question

我有以下查询:

SELECT 
DISTINCT (TK.TICKETID),
TK.DESCRIPTION,
TK.CREATIONDATE,
TK.REPORTEDBY,
TK.OWNER,
WF.ASSIGNCODE
FROM ticket TK
INNER JOIN wfassignment WF on WF.OWNERID = TK.TICKETUID
WHERE TK.status not in ('ЧЕРНОВИК', 'ЗАКРЫТ', 'ВЫПОЛНЕН') AND WF.ASSIGNSTATUS not in ('COMPLETE', 'INACTIVE')
ORDER BY TK.TICKETID;

但它返回 TK.TICKETID 属性中的重复项。如果我删除其他属性一切正常。
例如

TK.TICKETID TK.DESCRIPTION TK.CREATIONDATE  TK.REPORTEDBY  TK.OWNER     WF.ASSIGNCODE
О1013249    Право доступа   02.06.14        CHERNOVDK      SKACHKOVSV   NOVIKOVVA
О1013249    Право доступа   02.06.14        CHERNOVDK      SKACHKOVSV   PRITULADV
О1013249    Право доступа   02.06.14        CHERNOVDK      SKACHKOVSV   SVESHNIKOVAV

M.b.我的问题很简单，但我自己无法解决。
将非常适合任何形式的帮助。

Answer 1

试试这个:

SELECT 
TK.TICKETID,
TK.DESCRIPTION,
TK.CREATIONDATE,
TK.REPORTEDBY,
TK.OWNER,
max(WF.ASSIGNCODE)
FROM ticket TK
INNER JOIN wfassignment WF on WF.OWNERID = TK.TICKETUID
WHERE TK.status not in ('ЧЕРНОВИК', 'ЗАКРЫТ', 'ВЫПОЛНЕН') AND WF.ASSIGNSTATUS not in ('COMPLETE', 'INACTIVE')
group by
TK.TICKETID,
TK.DESCRIPTION,
TK.CREATIONDATE,
TK.REPORTEDBY,
TK.OWNER
ORDER BY TK.TICKETID;