firebase - 如何从 auth.user.onDelete 触发器中删除文档集合和所有嵌套数据

Question

目前，删除用户数据的逻辑如下:

import * as admin from 'firebase-admin';
import * as functions from 'firebase-functions';

const firestore_tools = require('firebase-tools');

admin.initializeApp();

const Auth = admin.auth();
const UsersCollection = admin.firestore().collection(`users`);

exports.deleteUserDocuments = functions.auth.user().onDelete((user) => {
  const userID = user.uid;

  UsersCollection.doc(userID)
      .delete({})
      .catch(error => {
        return error
      });
});

但是由于用户文档记录包含包含其他文档和集合的嵌套集合，因此它们仍然被保留: When you delete a document, Cloud Firestore does not automatically delete the documents within its sub-collections
我进行了一些研究，并找到了有关如何创建可调用函数的文档:
https://firebase.google.com/docs/firestore/solutions/delete-collections

但我想知道是否可以从 auth.user.onDelete 执行这个逻辑扳机？

更新解决方案

const firestore_tools = require('firebase-tools');

exports.deleteUserDocuments = functions.auth.user().onDelete((user) => {
    const userID = user.uid;
    const project = process.env.GCLOUD_PROJECT;
    const token = functions.config().ci_token;
    const path = `/users/${userID}`;

    console.log(`User ${userID} has requested to delete path ${path}`);

    return firestore_tools.firestore
        .delete(path, {
            project,
            token,
            recursive: true,
            yes: true,
        })
        .then(() => {
            console.log(`User data with ${userID} was deleted`);
        })
});

Answer 1

您可以在您想要的任何触发器中运行您想要的任何代码。触发器的类型与您可以运行的代码类型没有任何关系。